All categories

2 years ago

Which of the following statements about the picture is true

Mathematics

1 answer:

Contact [7]2 years ago

7 0

Answer:

Step-by-step explanation:

The figure shows you AR > AT. Since AX is the same for both triangles, angle AXR must be greater than angle AXT. This means AX is not the bisector of angle X.

Since AT is perpendicular to XT, it cannot be the perpendicular bisector of XT. That bisector will intersect XT at its midpoint, not its end.

The marked distances show you that A is different distances from T and R.

The only statement that makes any sense is ...

Point A is not on a bisector.

You might be interested in

Greatest to least 1.11 , 0.111 , 1.01 , 1.001

andreyandreev [35.5K]

1.11, 1.01, 1.001, .111

3 0

3 years ago

Read 2 more answers

3.05kilograms to grams

stira [4]

Answer:

3050 grams

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find an equivalent fractions for each given fraction 60/12

evablogger [386]

Very easy to do this.

60/12 is your fraction.

Multiply numerator and denominator by the same number.

60*2/12*2 = 120/24

120/24 = 5

You can also simplify.

60/12 = 5

12/12 = 1

5/1 = 5

60/12 = 5

8 0

3 years ago

Read 2 more answers

How to divide this? WITH SOLUTION i need the answer plss

Olin [163]

Answer:

Step-by-step explanation:Please mark me as the brainlyest

4 0

3 years ago

Given that curl F = 2yi – 2zj + 3k, find the surface integral of the normal component of curl F (not F) over (a) the open hemisp

Dimas [21]

Use Stokes' theorem for both parts, which equates the surface integral of the curl to the line integral along the surface's boundary.

a. The boundary of the hemisphere is the circle $x^2+y^2=9$ in the plane $z=0$ , where the curl is $\mathrm{curl}\vec F=2y\,\vec\imath+3\,\vec k$ . Green's theorem applies here, so that

$\displaystyle\iint_S\mathrm{curl}\vec F\cdot\mathrm d\vec S=\int_{\partial S}\vec F\cdot\mathrm d\vec r=3\int_{x^2+y^2=9}\mathrm d\vec r$

which means the value of the line integral is 3 times the area of the circle, or $27\pi$ .

b. The closed sphere has no boundary, so by Stokes' theorem the integral is 0.

7 0

3 years ago