V = 1,005.7 rounded off to one decimal place
Because:
Volume of a cylinder = πr²h
V = 22/7 x 4 x 4 x 20
V = 1,005.7
Answer: D is the correct answer
Step-by-step explanation:
Just took the test
Answer:
The volume of the region after being rotated is 603.186 unit³
Step-by-step explanation:
Here we have the shape formed by the region is that of a hollow cylinder with thickness 4 and length 6 with radius of opening at center = 2
Therefore, the volume is
πR²L - πr²L = πL(R² - r²)
Where:
R = Outer radius of the cylinder = 4 + 2 = 6
r = inner radius = 2
L = Length of the cylinder = 6
Therefore we have
Volume = π×6×(6² - 2²) = 603.186 unit³.
Solve for B by simplifying both sides of the equation, then isolating the variable. So in this case B=A....
<u>Solution-</u>
A pebble is dropped into a calm pond, causing ripples in the form of concentric circles.
The radius of the outer ripple is given by r(t)= 0.6t,
where t is the time in seconds after the pebble strikes the water.
The area of the circle is given by the function 
(a ◦ r)(t) = a(r(t)) ( ∵ Using function composition / plugging in the second function into the first function)
⇒![a(r(t))=a[0.6t]=(\pi)(0.6t)^2=0.36 \pi t^2](https://tex.z-dn.net/?f=a%28r%28t%29%29%3Da%5B0.6t%5D%3D%28%5Cpi%29%280.6t%29%5E2%3D0.36%20%5Cpi%20t%5E2)
∴ This is the expression for area of circle of outermost ripple, at time t after the pebble strikes the water.