The x-intercept of the equation would be (4, 0), and the y-intercept would be (0, 10).
To find the x and y intercepts, you need to substitute in x and y as 0 respectively because the x-intercept occurs when y = 0, and the y-intercept occurs when x = 0.
Substituting in y as 0 to get the x-intercept:
5x + 2(0) = 20
5x = 20
÷ 5
x = 4
Substituting in x = 0 to find the y-intercept:
5(0) + 2y = 20
2y = 20
÷ 2
y = 10
Therefore the final intercepts are (4, 0) and (0, 10)
I hope this helps!
