Can someone please answer. There is a picture. It is only one question. Thank you so much!

What is the equation of the rational function g(x) and its corresponding slant asymptote?

bija089 [108]

The solution to the Questions are

The alternate hypothesis demonstrates that there are two possible outcomes for the test.

Decision rule: If z > 2.05 or z<-2.05, reject H0

z=2.59

The two-tailed nature of the test is shown by the alternative hypothesis.
The result of the test yields the following P-value: 0.0096

<h3>What is the alternate hypothesis?</h3>

(a)

The alternate hypothesis demonstrates that there are two possible outcomes for the test.

(b)

Here we have

$n_{1}=40,\\\\ \bar{x}_{1}=102,\sigma_{1}=5,n_{2}=50,\bar{x}_{2}=99,\sigma_{2}=6$

(b)

Here the test is two-tailed. So for $\alpha =0.04$ , the critical values of the z-test are -2.05 and 2.05.

Decision rule: If z > 2.05 or z<-2.05, reject H0

(c)

Test statistics will be

$z=\frac{(\bar{x}_{1}-\bar{x}_{2})-(\mu_{1}-\mu_{2})}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}} \\\\\\z=\frac{(102-99)-(0)}{\sqrt{\frac{5^{2}}{40}+\frac{6^{2}}{50}}}$

z=2.59

(d)

The two-tailed nature of the test is shown by the alternative hypothesis.

(e)

The result of the test yields the following P-value: 0.0096

Read more about P-value

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4 0

2 years ago

What are the zeros of the function

aleksklad [387]

Answer:

Image result for What are the zeros of the function

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Description

DescriptionIn mathematics, a zero of a real-, complex-, or generally vector-valued function, is a member of the domain of such that vanishes at; that is, the function attains the value of 0 at, or equivalently, is the solution to the equation. A "zero" of a function is thus an input value that produces an output of

4 0

3 years ago

PLZZZZ HEEELLPPP!!!!!!

butalik [34]

Answer is tan inverse6/7

4 0

3 years ago

Read 2 more answers

Calculate m∠ADC. Round to the nearest thousandth.

stira [4]

Answer: $54.508^{\circ}$

Step-by-step explanation:

Let the angle ADC = x degree

Since, By the given diagram, In triangle BDC,

$\frac{BC}{DC} = tan27^{\circ}$

⇒ $\frac{BC}{19.6} = tan27^{\circ}$

⇒ $BC = 19.6\times tan 27^{\circ}$

⇒ $BC = 9.98669881009$

Now, In triangle ADC,

$tan x =\frac{AC}{DC}$

⇒ $tan x =\frac{AB+BC}{DC}$

⇒ $tan x =\frac{17.5+9.98669881009}{19.6}$

⇒ $tan x =\frac{27.4866988101}{19.6}$

⇒ $tan x =1.40238259235$

⇒ $x = 54.508389368\text{ degree} \approx 54.508^{\circ}$

4 0

3 years ago

I have to find the slope and the y-intersect from these graphs. It would mean alot if someone could help with at least one of th

Sati [7]

Answer:

Alright bear with me, this is gonna be a long one.

<u>The Y INTERCEPT</u>

So the y-intercept is going to be where the line intersects the Y-AXIS. The y-axis is the vertical part of the graph with the numbers on it.

So, for the first one, the line goes through the origin which means that that the y intercept is going to be (0,0)

The next one, the line intersects the y-axis at (0,1)

Here's a tip: the y-intercept will always have 0 as it's x coordinate.

<u>The Slope</u>

Alright, the slope of a vertical line can be found using an equation. Most typically people will describe the slope as RISE/RUN meaning how many units you move up "rise" and how many units you move horizontally "run" to touch the line. Of course, it's easier when you can identify points.

So to make this a little bit easier to understand, I will show you how to use the equation to find the slope.

$\frac{y2-y1}{x2-x1}$