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Reptile [31]
3 years ago
13

Find the value of x ASAP

Mathematics
1 answer:
e-lub [12.9K]3 years ago
6 0

The correct answer is 9.

Because they share a common angle at the top, we know that we can create a proportion using similar sides.

\frac{Outside LEFT}{Bottom LEFT} = \frac{Outside RIGHT}{Bottom RIGHT}

\frac{12}{8} = \frac{x}{6}

Now we can cross multiply to solve.

12*6 = 8*x

72 = 8x

9 = x

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Here you will divide 500 by 6 to get the girl students, and 500 by 5 to get boys.
7 0
3 years ago
PLEASE HELP FAST
Juliette [100K]

Answer:

120 ft ^2

Step-by-step explanation:

Volume= lwh

Volume= 16(3)(2 1/2)

Volume= 120 ft^2

5 0
4 years ago
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Which table shows a proportional relationship?
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I think the first one
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The diameter of a circle is 32 yards. What is the circle's area?
elixir [45]

Answer:

3216.9

Step-by-step explanation:

6 0
4 years ago
According to a 2009 Reader's Digest article, people throw away approximately 11% of what they buy at the grocery store. Assume t
expeople1 [14]

Answer:

0.14% probability that the sample proportion exceeds 0.2

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 108, p = 0.11

So

\mu = E(X) = np = 108*0.11 = 11.88

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{108*0.11*0.89} = 3.2516

What is the probability that the sample proportion exceeds 0.2

This is 1 subtracted by the pvalue of Z when X = 0.2*108 = 21.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21.6 - 11.8}{3.2516}

Z = 2.99

Z = 2.99 has a pvalue of 0.9986

1 - 0.9986 = 0.0014

0.14% probability that the sample proportion exceeds 0.2

8 0
4 years ago
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