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dexar [7]
3 years ago
14

Emily and Tyson each surveyed 10 people in a community. The people were asked how many years they have lived in their current ho

mes. The table shows mean, median and range for the data from each survey. Based on the data, what conclusion can be made about the range number of people in the community that have lived in their current homes *
It is less than 20 years
It is greater than 20 years
It is exactly 24 years
It cannot be determined
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0

Answer:

it is less then 20 years

Step-by-step explanation:

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2 years ago
What is the domain of the function y=3 in x graphed below?
Jet001 [13]
What is the domain of the function y=3 in x graphed below?

Domain is x>0, ln (0) is undefined and there is no negative ln.
3 0
3 years ago
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Where is the blue dot on the number line?
Daniel [21]

Answer:

Near 3.2

Step-by-step explanation:

6 0
3 years ago
If f(x)=x^3-x+2, then (f^-1)'(2)
yawa3891 [41]

Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,

f\left(f^{-1}(x)\right) = x

\implies f^{-1}(x)^3 - f^{-1}(x) + 2 = x

which is a cubic polynomial in f^{-1}(x) with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).

Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.

f'(x) = 3x² - 1 = 0   ⇒   x = ±1/√3

So, we have three subsets over which f(x) can be considered invertible.

• (-∞, -1/√3)

• (-1/√3, 1/√3)

• (1/√3, ∞)

By the inverse function theorem,

\left(f^{-1}\right)'(b) = \dfrac1{f'(a)}

where f(a) = b.

Solve f(x) = 2 for x :

x³ - x + 2 = 2

x³ - x = 0

x (x² - 1) = 0

x (x - 1) (x + 1) = 0

x = 0   or   x = 1   or   x = -1

Then \left(f^{-1}\right)'(2) can be one of

• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);

• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or

• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)

6 0
2 years ago
This exercise involves the formula for the area of a circular sector. The area of a circle is 700 m2. Find the area of a sector
mezya [45]

Answer:

334.4 m²

Step-by-step explanation:

The formula for the area of a sector is given as:

1/2 × r² × θ

Where θ = Central angle

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The formula for the area of a circle = πr²

r = Radius of a circle

r² = Area / π

r = √Area / π

r = √700/π

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Therefore, the area of the sector

= 1/2 × r² × θ

= 1/2 × 14.93² × 3 rad

= 334.35735 m²

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4 0
2 years ago
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