All categories

2 years ago

So yeah can anyone help me out be a tone

Mathematics

1 answer:

Brut [27]2 years ago

3 0

Answer:

p = -4

Step-by-step explanation:

-3( 2+4p) + 7 = 49

Subtract 7 from each side

-3( 2+4p) + 7 -7= 49-7

-3( 2+4p) = 42

Divide by -3

-3( 2+4p) /-3 = 42/-3

( 2+4p) = -14

Subtract 2 from each side

2+4p-2 = -14-2

4p = -16

Divide by 4

4p/4 = -16/4

p = -4

You might be interested in

A store buys shirts from

Anna007 [38]

Answer:

1.25*12=15

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

An object is launched straight up into the air at an initial velocity of 64 feet per second it is launched from a height of 6 fe

blondinia [14]

H is 24 You’re very welcome

8 0

3 years ago

Math be hard- Can ya help?

horrorfan [7]

Answer:

1/8

Step-by-step explanation:

The slope equation for this problem is

y2-y1

--------

x2-x1

So the y2=4, y1=3, x2=8, and x1=0

4-3 =1

----- --

8-0 =8

Which is 1/8

7 0

2 years ago

Read 2 more answers

Answer the problem :)

Tomtit [17]

The domain is the value of x. In this case, -3≤x≤7
the range is the value of y. in this case, -1≤y≤9

this is not a function, because the same x value has two corresponding y values. For example, when x=5, y=0 or y=8

It IS a function if every x value has only one corresponding y value.

5 0

2 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

3 years ago