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Dimas [21]
3 years ago
11

Find the volume for 30 points.

Physics
1 answer:
Nina [5.8K]3 years ago
5 0

Answer:

336.78 cubic feet

Explanation:

total volume= volume of cuboid + volume of cylinder

= lxbxh + π r^2h

= 9x7x4 + 3.14x(3)^2 x3

= 252+ 84.78

= 336.78 cubic feet

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Type the correct answer in each box. Use numerals instead of words.
ser-zykov [4K]

Answer:

6.23 newtons per second?

Explanation:

4 0
3 years ago
A 1 pF capacitor is connected in parallel with a 2 pF capacitor, the parallel combination then being connected in series with a
asambeis [7]

Hi there!

We can approach this problem in many ways, but to show you how I arrive to the final conclusion, I will begin by solving the circuit with an assigned value for the power source.

Let's use a power source value of 6V (produces nice numbers).

Recall the following rules.

Capacitors in series:

  • Voltage ADDS up.
  • Charge is EQUAL across each.
  • Total capacitance uses the reciprocal rule.

Capacitors in parallel:

  • Voltage is EQUAL across each.
  • Charge ADDS up.
  • Total capacitance is simply the sum.

Solving for total capacitance:
C_P = 1 + 2 = 3 pF\\\\C_T = \frac{1}{\frac{1}{3} + \frac{1}{3}} = 1.5 pF

Using rules for capacitors in series and parallel, the total capacitance of the circuit is 1.5 pF.

Thus, the total charge is:
Q = C_TV\\Q = 1.5 pF * 6 V = 9 pC

9 pC will go through the parallel combination and the individual capacitor in series with the combination.

Since the voltage adds up, we can find the amount of voltage across the 3pF capacitor with the remaining going through the branches of the parallel combination.

V = \frac{Q}{C}\\\\V = \frac{9pC}{3pF} = 3V

Therefore, 3V goes through each branch since 6V - 3V = 3V.

Solving for the charge for each capacitor:
Q  = CV\\Q = (1 pF)(3V) = 3pC\\\\Q = (2pF)(3V) = 6pC\\\\Q = (3pF)(3V) = 9pC

<u>Thus, the capacitor with the greatest charge is the 3 pF capacitor. </u>

To explain without all of the work above, the equivalent capacitance of the parallel combination (1 pF + 2pF = 3pF) is equivalent to the capacitance of the capacitor in series (3pF). Thus, the voltage across the parallel capacitors (since voltage is the same across branches in parallel) and the series capacitor is equal. However, since charge SUMS UP for capacitors in parallel, they would have less charge than the single capacitor in series.

5 0
2 years ago
A ladder 5.0 m long leans against a wall inside a spaceship. From the point of view of a person on the ship, the base of the lad
andriy [413]

Answer:

the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

Explanation:

Given the data in the question and as illustrated in the diagram below.

speed of the ship v = 0.90c

base of the ladder from the wall x₀ = 3.0 m

top of the later above the floor y = 4.0 m

we determine angle θ.

from the diagram,

tanθ = y/x₀

tanθ = y / x₀√( 1 - v²/c² )

we substitute

tanθ = 4.0 / 3.0√( 1 - ((0.9c)²/c²) )

tanθ = 4.0 / 3.0√( 1 - ((0.9²)c²/c²) )

tanθ = 4.0 / 3.0√( 1 - (0.9²) )

tanθ = 4.0 / 3.0√( 1 - 0.81 )

tanθ = 4.0 / 3.0√0.19

tanθ = 4.0 / 1.30766968

tanθ = 3.058876

θ = tan⁻¹( 3.058876 )

θ = 71.8965 ≈ 71.9°

Therefore, the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

3 0
3 years ago
Three resistors of 4.0, 6.0, and 10.0 Ω are connected in parallel. If the combination is connected in series with a 12.0-V batte
Grace [21]

Answer:

0.536 A

Explanation:

From the question,

The combined resistance of the parallel connection is given as

1/Rt = 1/4+1/6+1/10

Rt = 120/15

Rt = 8 ohms.

Since the the combination is connected in series with a 10 ohms resistor,

Rt' = 8+10 = 18 ohms.

Current flowing through the series circuit

I = V/Rt'

V = 12 V, Rt' = 18 ohms

I = 12/18

I = 0.67 A.

Therefore voltage across the combined resistor

V' = 8(0.67)

v' = 5.36 V.

Since the resistors a connected in parallel, the same voltage drop across them.

Therefore, current through the 10 ohms

Ix = 5.36/10

Ix = 0.536 A

5 0
3 years ago
A bicyclist rides 1.59 km due east, while the resistive force from the air has a magnitude of 7.00 N and points due west. The ri
kramer

Answer:

The required work done by the resistive force = -22.3 kJ

Explanation:

We understand that the amount of work done for a force F and displacements is provided as the product of force multiplied by displacement, which can be represented as W = F.S

Now, when the cyclist travels east and returns west, the force and displacement directions will be opposite and they make an angle 180 degrees apart.

∴

W = -2 × 7.00 × 1590

W = -22260 J

W = -22.3 kJ

8 0
3 years ago
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