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kicyunya [14]
3 years ago
8

How can a cyclist's acceleration change even if its velocity remains constant?

Physics
1 answer:
aleksley [76]3 years ago
5 0

It can't.  Acceleration IS a change in velocity.


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If a sound wave travels through air at a speed of 345 m/s, what would be the frequency of a 0.80 m long wave?
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Answer:

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Explanation:431.3

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Answer:Weight is the result of gravity . The gravitational field strength of Earth is 10 N/kg (ten newtons per kilogram). This means an object with a mass of 1 kg would be attracted towards the centre of Earth by a force of 10 N. We feel forces like this as weight.

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A weightlifter exerts an upward force on a 1000-N barbell and holds it at a height of 1 meter for 2 seconds. Approximately how m
Alex73 [517]

Amount of work done is zero and so power = 0 watts.

<u>Explanation:</u>

Power is the rate at which work is done, or W divided by delta t. Since the barbell is not moving, the weightlifter is not doing work on the barbell.Therefore, if the work done is zero, then the power is also zero.It may seem unusual that the data given in question is versatile i.e. A weightlifter exerts an upward force on a 1000-N barbell and holds it at a height of 1 meter for 2 seconds. But, still the answer is zero watts , this was a tricky question although conceptual basis of question was good! Power is dependent on amount of work done which is further related to displacement and here the net displacement is zero ! Hence, amount of work done is zero and so power = 0 watts.

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A person kicks a rock off a cliff horizontally with a speed of 20 m/s. It takes 7.0 seconds to hit the ground.
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A ball is thrown upward. The total time the ball remains in the air is 14 s. a) With what speed was the ball thrown upward? b) W
wolverine [178]

Answer:

a) Vi = 137.2 m/s

b) h = 960.4 m

Explanation:

a)

In order to find the initial speed we will use first equation of motion:

Vf = Vi + gt

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Vf = Final velocity = 0 m/s (since ball stops at highest point)

Vi = Initial Velocity = ?

g = - 9.8 m/s² (negative sign for upward moyion)

t = time interval = 14 s

Therefore,

0 m/s = Vi + (-9.8 m/s²)(14 s)

<u>Vi = 137.2 m/s</u>

<u></u>

b)

Now, we use second equation of motion to find height (h):

h = Vi t + (1/2)gt²

h = (137.2 m/s)(14 s) + (1/2)(-9.8 m/s²)(14 s)²

h = 1920.8 m - 960.4 m

<u>h = 960.4 m</u>

5 0
3 years ago
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