Answer:
v = 4374 Km/h
Explanation:
Given that,
Mass of the smaller object, m = 2 Kg
Mass of the bigger object, M = 1500 Kg
Velocity of the bigger object, V = 1.62 m/s
Velocity of the smaller object, v = ?
The product of its mass and velocity of a body is equal to its linear momentum. It is given by the formula
p = mv Kg m/s
To find the momentum of the bigger object, substitute M and V in the above equation
p = 1500 Kg x 1.62 m/s
= 2430 Kg m/s
The velocity imparted to the small body to attain this momentum is given by the relation
v = p/m m/s
= 2430 Kg m/s / 2 Kg
= 1215 m/s
By converting the velocity to Km/h
v = 4374 km/h
Hence, the velocity of the 2 Kg object is v = 4374 km/h
The answer is increased. A power factor of one or "unity power factor" is the aim of any electric utility business from the time when if the power factor is less than one, they have to give more current to the user for an assumed amount of power use. In so doing, they gain more line harms.
Answer: According to Newton's third law of motion, whenever one object exerts a force on a second object, the second object exerts an equal and opposite force on the first object. These two forces are called action and reaction forces.
Explanation:
No cap i know
Answer:
D) Repeating the experiment several times and comparing the results
Explanation:
Replication of experiments allows scientists to see patterns and trends in the results of the experiments. It helps the scientist performing the experiment to see if there is precision in the results gotten and to test the integrity of the data. The results of several repetitions of the experiment can be compared and tested for consistency.
Performing this experiment severally will make the scientist know whether the dissolved oxygen contents gotten in each of the tanks are close to each other. If the results are wide apart, then the data lacks integrity and should not be used.
The answer is CFC – 22 or HCFC - 22. To locate leaks, it is
easily accomplished using a pressure – regulated dry nitrogen charge with CFC –
22. But some technicians prefer to use Refrigerant – 22 (HCFC – 22) to
pressurize the system without the use of nitrogen. CFC – 22 is also known as Chlorodifluoromethane.
This is a hydrochlorofluorocarbon (HCFC). This is better recognized as HCFC-22, or R-22. It is usually
used as a propellant and refrigerant. While HCFC
– 22 is also known as class II hydrochlorofluorocarbon refrigerant that is less
harmful to the ozone than R -12. If HCFC – 22 is used for leak testing, all
refrigerant must be first detached from the system. After the leak test, HCFC –
22 should be remove before putting any other refrigerant. Do not mix refrigerants.
Both HCFC – 22 and R -134a fall into the kind of refrigerants known as
combustible. If exposed to oxygen, they will burn when under pressure or
exposed to high temperatures.
