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ss7ja [257]
3 years ago
6

Type the correct answer in each box. Use numerals instead of words.

Physics
1 answer:
ser-zykov [4K]3 years ago
4 0

Answer:

6.23 newtons per second?

Explanation:

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Parallel light rays with a wavelength of 563 nm fall on a single slit. On a screen 3.30 m away, the distance between the first d
MrMuchimi

Answer:

The width of the slit is 0.4 mm (0.00040 m).

Explanation:

From the Young's interference expression, we have;

(λ ÷ d) = (Δy ÷ D)

where λ is the wavelength of the light, D is the distance of the slit to the screen, d is the width of slit and Δy is the fringe separation.

Thus,

d = (Dλ) ÷ Δy

D = 3.30 m, Δy = 4.7 mm (0.0047 m) and λ = 563 nm (563 ×10^{-9} m)

d = (3.30 × 563 ×10^{-9} ) ÷ (0.0047)

  = 1.8579 × 10^{-6} ÷ 0.0047

  = 0.0003951 m

d = 0.00040 m

The width of the slit is 0.4 mm (0.00040 m).

3 0
3 years ago
. A 79 g sample of water at 21oC is heated until it becomes steam with a temperature of 143oC. Find the change in heat content o
mote1985 [20]

Answer:

40479.6 J

Explanation:

Applying,

q = cm(t₂-t₁).................... Equation 1

Where q = change in heat content of the system, c = specific heat capacity of the system, m = mass of the system, t₁ = initial temperature, t₂ = final temperature.

From the question,

Given: m = 79 g = 0.079 kg, t₁ = 21°C, t₂ = 143°C

Constant: c = 4200 J/kg.°C

Substitute these values into equation 1

q = 4200(0.079)(143-21)

q = 331.8(122)

q = 40479.6 J

4 0
3 years ago
Find the acceleration if a 32.5 N force is<br> used on an object that has a mass of<br> 128.6 kg.
Sholpan [36]

Answer:

Acceleration=3.95

Explanation:Use the formula a=m/f

a=128.6/32.5

a=3.95

3 0
3 years ago
The gravitational force between two objects has a magnitude of F. If both masses were doubled and the distance between them doub
Fofino [41]

Answer:

F' = F

Explanation:

The gravitational force of attraction between two objects can be given by Newton's Gravitational Law as follows:

F = \frac{Gm_1m_2}{r^2}

where,

F = Force of attraction

G = Universal gravitational costant

m₁ = mass of first object

m₂ = mass of second object

r = distance between objects

Now, if the masses and the distance between them is doubled:

F' = \frac{G(2m_1)(2m_2)}{(2r)^2}\\\\F' = \frac{Gm_1m_2}{r^2}

<u>F' = F</u>

7 0
3 years ago
Use this formula to solve this problem:
Maslowich
Well, you gave us the formula to calculate power from work and time,
but you didn't give us the formula for work.  We have to know that.

             Work = (force) x (distance)

The work to raise Sara to the top of the hill is

               Work = (300 N) x (15 meters)

                         =   4,500 newton-meters  =  4,500 joules .

Now we're ready to use the formula that you gave us.  (Thank you.)

                Power = (work) / (time)

                            = (4,500 joules) / (10 seconds)

                            450 joules/second  =  450 watts.       
6 0
3 years ago
Read 2 more answers
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