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Setler [38]
3 years ago
13

Determine the minimum applied force p required to move wedge a to the right. the spring is compressed a distance of 175 mm. negl

ect the weight of a and
b. the coefficient of static friction for all contacting surfaces is μs=0.35. neglect friction at the rollers.
Physics
1 answer:
BARSIC [14]3 years ago
6 0
<span>b. The coefficient of static friction for all contacting surfaces is μs=0.35. neglect friction at the rollers.

</span>
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Air in the atmosphere is heated by the ground this warm air then rises and cooler air falls this is an example of what type of p
Alona [7]
The answer for both is ‘B’
8 0
3 years ago
A particle has a charge of -4.25 nC.
SpyIntel [72]

Answer:

-611.32 N/C

0.43723 m

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

q = Charge = -4.25 nC

r = Distance from particle = 0.25 m

Electric field is given by

E=\dfrac{kq}{r^2}\\\Rightarrow E=\dfrac{8.99\times 10^9\times -4.25\times 10^{-9}}{0.25^2}\\\Rightarrow E=-611.32\ N/C

The magnitude is 611.32 N/C

The electric field will point straight down as the sign is negative towards the particle.

E=\dfrac{kq}{r^2}\\\Rightarrow r=\sqrt{\dfrac{kq}{E}}\\\Rightarrow r=\sqrt{\dfrac{8.99\times 10^9\times 4.25\times 10^{-9}}{13}}\\\Rightarrow r=1.71436\ m

The distance from the electric field is 1.71436 m

4 0
3 years ago
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To prevent accidental electric shock, most electrical equipment is A. painted. B. isolated. C. coated. D. grounded.
Nesterboy [21]
D. It is Grounded below ground 
4 0
3 years ago
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Your study buddy claims that an electron always experiences a force in an electric field, but not always in a magnetic field. do
timurjin [86]
It's true charged particles are always acted on by an electric field.when the velocity of the electron is parallel to the magnetic field, the magnetic force vanishes.
4 0
3 years ago
What is the wavelength of a wave with a frequency of 262 hz and a speed of 343 m/s
Tamiku [17]

Heya!!

For calculate wavelength, lets applicate formula:

                                                      \boxed{\lambda = V/f}

                                                   <u>Δ   Being   Δ</u>

                                            f = Frequency = 262 Hz

                                            v = Velocity = 343 m/s

                                             \lambda = Wavelenght = ?

⇒ Let's replace according the formula:

\boxed{\lambda = 343\ m/s / 262\ Hz }

⇒ Resolving

\boxed{\lambda = 1,3 \ m}

Result:

The wavelength is <u>1,3 meters.</u>

Good Luck!!

8 0
3 years ago
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