Answer:
- The equation that represent the cost C of renting a car and driving x miles is C = $39.11 + $0.50x
- $130 can travel 181.32 miles
Step-by-step explanation:
From the question, a rental company rents a luxury car at a daily rate of 39.34 $ plus $.50 per mile, that is
$0.50 is added to the initial $39.34 for every mile.
The equation that represent the cost C of renting a car and driving x miles is
C = $39.34 + $0.50x
Now, to determine how many miles 130$ can travel,
we will put C = $100, and determine x in the above equation
$130 = $39.34 + $0.50x
$130 - $39.34 = $0.50x
$90.66 = $0.50x
x = $90.66/$0.50
x = 181.32
Hence, $130 can travel 181.32 miles
Keep, Change, Flip
5/7 x 4/3 = ?
<span>B. ∠E and ∠H are alternate exterior angles</span>
Because <span>STVU is an isosceles trapezoid
so SV = TU
</span><span>6x - 5 = 2x + 7
6x - 2x = 7 + 5
4x = 12
x = 3
answer
x = 3</span>
Answer:
Check the explanation
Step-by-step explanation:
Let
and
be sample means of white and Jesse denotes are two random variables.
Given that both samples are having normally distributed.
Assume
having with mean
and
having mean 
Also we have given the variance is constant
A)
We can test hypothesis as

For this problem
Test statistic is

Where

We have given all information for samples
By calculations we get
s=2.41
T=2.52
Here test statistic is having t-distribution with df=(10+7-2)=15
So p-value is P(t15>2.52)=0.012
Here significance level is 0.05
Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.
We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.