Answer:
See explanation
Explanation:
From Newton's law; the rate of change of momentum is proportional to the impressed force. Hence;
F.t = mv- mu
F= force
t= time
m= mass
V= final velocity
u = initial velocity
since u = 0, mv= 0
F= MV/t
F= 69.8 × 5.27/0.833
F= 442 N
Impulse = Ft= 442 × 0.833= 368 Ns
Answer:
<h2>
f₀ = 158.12 Hertz</h2>
Explanation:
The fundamental frequency of the string f₀ is expressed as f₀ = V/4L where V is the speed experienced by the string.
where T is the tension in the string and
is the density of the string
Given T = 600N and
= 0.015 g/cm = 0.0015kg/m

The next is to get the length L of the string. Since the string is stretched and fixed at both ends, 200 cm apart, then the length of the string in metres is 2m.
L = 2m
Substituting the derived values into the formula f₀ = V/2L
f₀ = 632.46/2(2)
f₀ = 632.46/4
f₀ = 158.12 Hertz
Hence the fundamental frequency of the string is 158.12 Hertz
Answer:
yes
Explanation:
this is true don't believe other people whether right or wrong
Answer:

Explanation:
given,
mass of the weight = 8 Kg
distance = 0.55 m
angle below horizontal = 30°
torque about shoulder




torque about his shoulder join is equal to 
<span>node spacing = half of wavelength = 3 cm
velocity = 10 cm/s = freq * wavelength
hench freq = 10/6 = 5/3 = 1.7 hz</span>