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kap26 [50]
3 years ago
15

Dos cargas de 1 pC estan a 1mm, la fuerza de interaccion entre dichas cargas es?​

Physics
1 answer:
Naddik [55]3 years ago
6 0

Answer:

La fuerza de interacción entre dichas partículas es 8.988\times 10^{-9}\,N.

Explanation:

Asumamos que las dos cargas son puntuales, puesto que la fuerza de interacción es netamente electrostática, es determinada por la Ley de Coulomb:

F = \frac{k\cdot q_{1}\cdot q_{2}}{r^{2}} (1)

Donde:

k - Constante electrostática, medida en newton-metros cuadrados por Coulomb cuadrado.

q_{1}, q_{2} - Carga eléctrica, medida en Coulomb.

r - Distancia entre las partículas, medida en metros.

Si sabemos que k = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}, q_{1} = q_{2} = 1\times 10^{-12}\,C y r = 1\times 10^{-3}\,m, entonces la fuerza de interacción entre ambas partículas es:

F = \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (1\times 10^{-12}\,C)^{2}}{(1\times 10^{-3}\,m)^{2}}

F = 8.988\times 10^{-9}\,N

La fuerza de interacción entre dichas partículas es 8.988\times 10^{-9}\,N.

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