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kap26 [50]
2 years ago
15

Dos cargas de 1 pC estan a 1mm, la fuerza de interaccion entre dichas cargas es?​

Physics
1 answer:
Naddik [55]2 years ago
6 0

Answer:

La fuerza de interacción entre dichas partículas es 8.988\times 10^{-9}\,N.

Explanation:

Asumamos que las dos cargas son puntuales, puesto que la fuerza de interacción es netamente electrostática, es determinada por la Ley de Coulomb:

F = \frac{k\cdot q_{1}\cdot q_{2}}{r^{2}} (1)

Donde:

k - Constante electrostática, medida en newton-metros cuadrados por Coulomb cuadrado.

q_{1}, q_{2} - Carga eléctrica, medida en Coulomb.

r - Distancia entre las partículas, medida en metros.

Si sabemos que k = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}, q_{1} = q_{2} = 1\times 10^{-12}\,C y r = 1\times 10^{-3}\,m, entonces la fuerza de interacción entre ambas partículas es:

F = \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (1\times 10^{-12}\,C)^{2}}{(1\times 10^{-3}\,m)^{2}}

F = 8.988\times 10^{-9}\,N

La fuerza de interacción entre dichas partículas es 8.988\times 10^{-9}\,N.

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Answer:

Earth's interior (Core)

Explanation:

The earth is comprised of 3 distinct layers namely the Core, the Mantle and the Crust, which are divided based on their composition as well as density.

The core of the earth is extremely very hot where the inner core remains solid and outer core acts a liquid. It is mainly comprised of iron, nickel and other siderophile elements.

A large amount of heat (energy) is radiated from this core region towards the surface of the earth. Due to this, the mantle rocks forms magma that creates the convection currents, where the hot and less dense magma rises upward and the cool and denser magma sinks to the bottom. This occurs continuously, as a result of which the lithospheric plates are forced to move over the less dense layer of asthenosphere.

Thus, the heat energy that drives the convection current in the mantle is provided from the interior (core) of the earth.

3 0
3 years ago
An 877 kg drag race car accelerates from rest to 116 km/h in 0.951 s. What change in momentum does the force produce? Answer in
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Answer:

The change in momentum is 28265.71  kg-m/s.

Explanation:

Given that,

Mass of a car, m = 877 kg

Initial velocity of the car, u = 0 (at rest)

Final velocity of the car, v = 116 km/h = 32.23 m/s

Time, t = 0.951 s

We need to find the change in momentum produced by the force. It can be calculated as the difference of final momentum and the initial momentum.

\Delta P=m(v-u)\\\\=877\times (32.23-0)\\\\=28265.71\ kg-m/s

So, the change in momentum is 28265.71  kg-m/s.

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Explanation:

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