Answer:
(B) π/12 + π/6 k
Step-by-step explanation:
Points of inflection are where f"(x) = 0 and changes signs.
f(x) = cos²(3x)
f(x) = (cos(3x))²
f'(x) = 2 (cos(3x))¹ × -sin(3x) × 3
f'(x) = -6 sin(3x) cos(3x)
Using double angle formula:
f'(x) = -3 sin(6x)
f"(x) = -3 cos(6x) × 6
f"(x) = -18 cos(6x)
0 = -18 cos(6x)
0 = cos(6x)
6x = π/2 + 2πk or 6x = 3π/2 + 2πk
We can simplify this to:
6x = π/2 + πk
x = π/12 + π/6 k
Answer:
Step-by-step explanation:
Answer:
Point-slope form:
y
−
4
=
−
2
(
x
+
3
)
Slope-intercept form:
y
=
−
2
x
−
2
Explanation:
Assuming you mean a line that passes through these two points, use point-slope form:
y
−
y
1
=
m
(
x
−
x
1
)
To find the slope, m, use the slope formula
m
=
y
2
−
y
1
x
2
−
x
1
(-3,4) and (1,-4):
m
=
−
4
−
4
1
+
3
m
=
−
8
4
=
−
2
Now, plug in the slope and either point into point-slope form:
y
−
4
=
−
2
(
x
+
3
)
To convert this to slope intercept form, isolate y and simplify:
y
−
4
=
−
2
x
−
6
y
=
−
2
x
−
2
Answer:
he would have to be at the mountain by 7:45
Step-by-step explanation:
if I'm not mistaken it would take him six hours in total to be up and down the mountain and 7:45 - 1:45 = 6
Answer:
Two geometrical shapes which are identical in shape and size are said to be congruent. We use the symbol '≅' to denote congruence.
Step-by-step explanation:
Answer:
.B.An orthocenter can be outside of its triangle
Step-by-step explanation:
The orthocenter of a triangle is the intersection of the point drawn perpendicular from the vertices of the triangle. While normal equilateral triangles for instance have their point of intersection drawn inside the triangle, the orthocenter of a triangle of an obtuse triangle is outside of the triangle. A right angled triangle has its orthocenter drawn at the vertex of the right angle and really inside the right angled triangle.