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2 years ago

Need help finding the area

Mathematics

2 answers:

alexgriva [62]2 years ago

5 0

Answer: 288 I think.

Step-by-step explanation: First you find the area of the first rectangle, then the second. You do this by splitting both rectangles and finding the area there. Add those up. Then you want to find you the area for the corners. Add that and there’s your answer.

kolezko [41]2 years ago

3 0

Answer:

256inches

Step-by-step explanation:

8×16 + 8×16

128+128=256

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Why is 24.625 irrational

Katen [24]

Its not irrational............

7 0

3 years ago

The function f is linear. If f(2) = 2 and f(-6)=6 find f(6)

lina2011 [118]

$The\ slope-intercept\ form:y=mx+b\\\\f(2)=2\to for\ x=2\to y=2\\f(-6)=6\to for x=-6\to y=6\\\\put\ in\ equation\ of\ the\ line:\\\\ -\left\{\begin{array}{ccc}2=2m+b\\6=-6m+b\end{array}\right\ \ \ |subtract\ sides\ of\ the\ equations\\----------\\.\ \ \ -4=8m\ \ \ \ \ |divide\ both\ sides\ by\ 8\\.\ \ \ \ \boxed{m=-\frac{1}{2}}\\\\put\ m=-\frac{1}{2}\ to\ equation\ 2=2m+b:\\\\2=2\cdot(-\frac{1}{2})+b\\2=-1+b\ \ \ \ |add\ 1\ to\ both\ sides\\\boxed{b=3}\\\\\boxed{\boxed{y=-\frac{1}{2}x+3}}$

$therefore:f(x)=-\frac{1}{2}x+3\Rightarrow f(6)=-\frac{1}{2}\cdot6+3=-3+3=0\\\\Answer:\boxed{f(6)=0}$

5 0

2 years ago

49–2ax –a^2–x^2 factor

vampirchik [111]

49–2ax –a^2–x^2

Extract the negative sign

= 49 - (a^2 +2ax +x^2)

Factor using a^2 + 2ab + b^2 = (a+b)^2

= 49 - (a+x)^2

Factor using a^2 - b^2 = (a-b)(a+b)

= ( 7- (a + x)) * (7 + (a + x))

= ( 7- a - x) * (7 + a + x)

4 0

3 years ago

What is the answer to (-7) x (3) x (-4)

azamat

Answer:

The answer is 84

Step-by-step explanation:

(-7)*(3)*(-4)

negatives cancel out: 7*3*4

Simplify: 84

7 0

3 years ago

Read 2 more answers

Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un

stira [4]

Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

Along width cement path, the length of region = $2w+15$

width = $2w+9$

Area of road with pool = $(2w+15) (2w+9)$

$= 4w^2+30w+18w+135\\\\=4w^2+48w+135$

Area of road = (Area of road with pool ) -(area of pool)

$\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\ w=-14\ or \ w=2$

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

8 0

3 years ago

Need help finding the area​

Need help finding the area