There exist a similar question where b = 68 instead of 6. First, determine the measure of the third angle, angle C,
m∠c = 180 - (55° + 44°) = 81°
Let x be the side AB, that which is opposite to angle C. Through the Sine Law,
68 / sin 44° = x / sin 81°
From the equation, the value of x is equal to 96.68. Thus, the answer is letter B.
First of all, just to avoid being snookered by a trick question, we should verify that these are really right triangles:
7² + 24² really is 25² , and 8² + 15² really is 17² , so we're OK there.
In the first one:
sin(one acute angle) = 7/25 = 0.28
the angle = sin⁻¹ (0.28) = 16.26°
the other acute angle = (90° - 16.26°) = 73.74°
In the second one:
sin(one acute angle) = 8/17 = 0.4706...
the angle = sin⁻¹ (0.4706...) = 28.07°
the other acute angle = (90° - 28.07°) = 61.93°
I'm sorry, but just now, I don't know how to do the
third triangle in the question.
Answer:
y = 50x + 25
Step-by-step explanation:
y = mx + b
Hi!
A is the answer:⏬⏬⏬⏬⏬⏬⏬⏬
The distance around a triangle, better noun as de "perimeter of a triangle"
is the total distance around the outside, which can be found by adding together the length of each side.
Perimeter (P) = Length A + Length B + Lenght C
In this case, we know that each side measure 2 \frac{1}{8}81 feet, 3 \frac{1}{2}21 feet, and 2 \frac{1}{2}21feet but we have to rewrite each one of this mixed fractions as improper fractions:
2 \frac{1}{8}81 = \frac{16 + 1}{8}816+1 = \frac{17}{8}817
3 \frac{1}{2}21 = \frac{6 + 1}{2}26+1 = \frac{7}{2}27
2 \frac{1}{2}21 = \frac{4 + 1}{2}24+1 = \frac{5}{2}25
Then we just add all of them to find the perimeter:
 = \frac{17 + 28 + 20}{8}817+28+20 = \frac{65}{8}865
A: The distance around a triangle is \frac{65}{8}865feet
