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maxonik [38]
3 years ago
12

How has the model of our solar system changed over time?

Physics
2 answers:
sineoko [7]3 years ago
7 0
It depends.<span>Ptolemy was one of the most famous astronomers who was convinced that or solar system was geocentric, or revolving around the earth. Then, Copernicus came around, along with Galileo, and the attempted to convince people that that wasn't true, but that we were revolving around the sun. In fact, if you're writing an essay, a good point to add would be that Galileo spent a large part of his life imprisoned for "disobedience of the (Roman) Gods.)"</span>
adoni [48]3 years ago
7 0

It always depends of how our solar system changed over time.

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What do the elements in group 17 of the periodic table have in common
yulyashka [42]
They are toxic and all non metals
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Sounds with frequencies too low for the human ear to hear are called what?
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Infrasound, I believe.
8 0
4 years ago
Read 2 more answers
A uniformly charged, thin ring has radius 15.0 cm and total charge +24.0 nC. An electron is placed on the ring’s axis a distance
djyliett [7]

Answer:

A. The electron will begin to move along the axis, towards the centre and the instantaneous velocity because the force acting on it depends largely on acceleration and x until it reaches maximum velocity at centre.

B. Veloctiy (Vb) = 1.66m/s

Explanation:

Given the following data

x(a) = 0.3m

x(b) = 0

q = 1.6×10^-19

Q = 24nc

r = 0.15m

Required: the motion of the electron and the velocity (Vb)

1. At point A the electron will begin to move along the axis from point A to point B, the magnitude of the electric field will change while moving which depends on that and this will produce instantaneous force which will later change and the acceleration will change too while moving, the velocity would reach maximum value at point B

2. Potential energy and kinetic energy are given by

U(a) + K(a) = U(b) + K(b). . .1

Initial P.E and K.E are given as

U(a) = kQ/√x²(a) + a2

By substitution, we have

U(a) = 9×10^9 × (-1.9×10^-19)×24×10^-9/√(0.15)²+(0.3²)

U(a) = -1.03×10^-16

Final P.E and K.E are given as

U(b) = KQ/√x²(b) + a2

By substitution, we have

U(b) = 9×10^9×(-1.9×10^-19)×24×10^-9/√(0.15)²+(0)²

U(b) = -2.3×10^16

3. By substitution into equation 1 becomes

-1.03×10^-6 - 2.3×10^-16 + MV²(b)/2

V(b) = √2×1.27×10^-16/9.1×10^31

V(b) = 1.66×10^7m/s

4 0
4 years ago
SOMEBODY PLEEASEEE HELP A STRUGGLING HIGHSCHOOLERRRR +(
CaHeK987 [17]

Explanation:

What is the weight of a 2.00-kilogram object on the surface of Earth?

2.00 N

4.91 N

9.81 N

19.6 N

Given parameters:

Mass of the object = 2kg

Unknown:

Weight of the object  = ?

Solution:

The weight of an object is the force of gravity acting on the object;

 Weight  =  mass x acceleration due to gravity

Acceleration due to gravity  = 9.8m/s²

 Now insert the parameters and solve;

    Weight  = 2 x 9.8 = 19.6N

A person weighing 785 Newtons on the surface of the Earth would weigh 47 Newtons on the surface of Pluto. What is the magnitude of the gravitational acceleration on the surface of Pluto?

1.7 m/s²

0.59 m/s²

0.29 m/s²

9.8 m/s²

Given parameters:

Weight on Earth  = 785N

Weight on Pluto = 47N

Unknown:

Acceleration due to gravity on Pluto = ?

Solution

The mass of the body both on Earth and Pluto is the same.

  Weight = mass x acceleration due to gravity

Now find the mass on Earth;

  Acceleration due to gravity on Earth  = 9.8m/s²

    785   = mass x 9.8

         mass  = \frac{785}{9.8}   = 80.1kg

So;

  Acceleration due to gravity on Pluto = \frac{Weight on Pluto}{mass }  

  Acceleration due to gravity  = \frac{47}{80.1}   = 0.59m/s²

5 0
3 years ago
At what time does the box have the greatest kinetic energy
Y_Kistochka [10]

Answer:

therefore, more kinetic energy! An object has the MOST kinetic energy when it's movement is the GREATEST.

Explanation:

3 0
3 years ago
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