Ask question

Ask question

All categories

3 years ago

13

Two lamps, each having reisistance of 3 Ohms, connect in a series. What current will flow if a voltage source of 5 V is connecte

d at input?

1 answer:

Ket [755]3 years ago

6 0

Total resistance will be R1 + R2.
And the formula will be I equals V over R.
V=5
I=?
R=6

I= 0,83 amps

You might be interested in

When a train first starts going down the railroad, it is very difficult for it to get going. When it comes to a stop, it has a h

Sveta_85 [38]

A train is a very big and heavy object, so the bigger the object is, the slower it will begin to move. With that said, bigger objects are also heavier and will move fast once going. Since the train is a huge and heavy object it will need longer time to slow down and come to a stop.

4 0

3 years ago

A mass is undergoing simple harmonic motion. When its displacement is 0, it is at its equilibrium position. At that moment, its

Nostrana [21]

Answer:

Its speed is maximum and its acceleration is zero

Explanation:

- Concerning the speed:

In a simple harmonic motion, the speed can be determined through the law of conservation of energy. In fact, we have that the total mechanical energy of the system, which is sum of elastic potential energy U and kinetic energy K, is constant:

$E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2$

where k is the spring constant, x is the displacement, m is the mass and v is the speed.

We see that when the displacement is 0, x = 0: this means that the elastic potential energy U is also 0, therefore the kinetic energy K is maximum, and so the speed v is also maximum.

- Concerning the acceleration:

According to Newton's second law, the acceleration of the system is proportional to the net force:

$a=\frac{F}{m}$

the net force is just the restoring force of the spring, given by Hooke's law:

$F=-kx$

So, the acceleration is

$a=-\frac{kx}{m}$

and we see that when the displacement is zero, x = 0, and so the acceleration is also zero.

4 0

4 years ago

Calculate the absolute pressure at an ocean depth of 100m. Density of water = 1.025x10^3 kg/m^3

Nana76 [90]

Answer:

I don't know sorry plz

Explanation:

8 0

3 years ago

A thin ring of radius R is uniformly charged with the total positive charge Q. 1. Find the electric field at distance h right ab

Paha777 [63]

Answer:

$E_{net} = \frac{k Q h}{(R^2 + h^2)^{\frac{3}{2}}}$

Explanation:

If charge Q is uniformly distributed over the ring then for small element of the ring the charge will be given as

$dq = \frac{Q}{2\pi R} dL$

now electric field due to this small element on the axis of ring at height "h" is given as

$dE = \frac{k dq}{R^2 + h^2}$

now since this electric field is radially in the direction of joining the position of charge to the given point

so net field due to ring will be along the axis of ring

so we have

$E_{net} = \int dEcos\theta$

$E_{net} = \int \frac{k dq}{R^2 + h^2} \frac{h}{\sqrt{R^2 + h^2}}$

$E_{net} = \frac{k Q h}{(R^2 + h^2)^{\frac{3}{2}}}$

4 0

3 years ago

A mass m1= 6.20 kg is moving North with a velocity of v1= 13.5m/sec when it collides perpendicularly with another mass m2= 4.40

JulijaS [17]

Answer:

Momentum of mass $m_{1}$ is 83·7 kg m/s towards north

Momentum of mass $m_{2}$ is 38·72 kg m/s towards east

Explanation:

Given

Mass of $m_{1}$ = 6·2 kg

Mass of $m_{2}$ = 4·4 kg

Velocity of mass $m_{1}$ = $v_{1}$ = 13·5 m/s

Velocity of mass $m_{2}$ = $v_{2}$ = 8·8 m/s

Momentum of mass $m_{1}$ = $m_{1}$ × $v_{1}$ = 6·2 × 13·5 = 83·7 kg m/s

Momentum of mass $m_{2}$ = $m_{2}$ × $v_{2}$ = 4·4 × 8·8 = 38·72 kg m/s

As mass $m_{1}$ is moving North, the direction of momentum will also be in that direction because the direction of momentum will be in the direction of velocity

As mass $m_{2}$ is moving East, the direction of momentum will also be in that direction because the direction of momentum will be in the direction of velocity

∴ Momentum of mass $m_{1}$ is 83·7 kg m/s towards north

∴ Momentum of mass $m_{2}$ is 38·72 kg m/s towards east

7 0

3 years ago