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sertanlavr [38]
4 years ago
10

George's highest target heart rate is 170. Yesterday on the stair stepper machine, his heart rate went to 172. What should he do

the next time he uses this machine to get the most effective workout?
Physics
2 answers:
Kruka [31]4 years ago
4 0
Take a break and catch his breath.
Nadya [2.5K]4 years ago
4 0
Your answer would be that he needs to use the settings of the machine to decrease the intensity. That way he's at exactly 170 or slightly below it.
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Question seems to be missing. Found it on google:

a) How long is the ski jumper airborne?

b) Where does the ski jumper land on the incline?

a) 4.15 s

We start by noticing that:

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d_x = v_x t

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tan \theta = \frac{\frac{1}{2}gt^2}{v_x t}= \frac{gt}{2v_x}\\t = \frac{2v_x}{g}tan \theta = \frac{2(28)}{9.8} tan 36^{\circ} =4.15 s

b) 143.6 m

Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:

d_x = v_x t = (28)(4.15)=116.2 m

d_y = \frac{1}{2}gt^2 = \frac{1}{2}(9.8)(4.15)^2=84.4 m

The distance covered along the slope is just the magnitude of the resultant displacement, so we can use Pythagorean's theorem:

d=\sqrt{d_x^2+d_y^2}=\sqrt{(116.2)^+(84.4)^2}=143.6 m

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3 years ago
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