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Zielflug [23.3K]
3 years ago
13

HELP ME PLZ and show ur work if u can

Mathematics
1 answer:
Ivahew [28]3 years ago
8 0
What you have down is correct
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Solve the formula for the perimeter of a rectangle with width W and length I for the length p=2w+2I
Bad White [126]
P= 2I + 2W, -2I -2W 
Solve for P by Simplifying both sides of the equations, then isolating the variable. 
6 0
3 years ago
Somebody please help me for gods sake I swear I’d do it but I have no idea what this is and it’s due today
Fed [463]

Answer:

Domain: (-∞,∞)

Range: (-4, ∞)

Transformation: y = | x - 2 | - 4  (parant function is y = | x | )

Increasing Values: (-4,∞)

Decreasing Values: (-∞,-4)

End Behavior: f(x) → + ∞ on both sides

Hope this helps!

6 0
3 years ago
Find the mistake. How would you solve this problem correctly? plz answer btw those a minus this is due at 11: 59
garik1379 [7]

Answer:

The mistake is in the second "problem" or the second part

Step-by-step explanation:

solve correctly by using pemdas when there are parenthesis but only "one" number (4) and a variable (x) you multiple (bring over the 6 and times both) leaving you with 6x + 24

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B9x%7D%5E%7B2%7D%20-%20%7B%28x%7D%5E%7B2%7D%20-%204%29%20%7B%7D%5E%7B2%7D%20
Alenkinab [10]

Answer:

{ x^2+3x-4}

Step-by-step explanation:

Factor top and bottom.

The numerator is a difference of two squares, and the denominator is a quadratic.

\frac{ {9x}^{2} - {(x}^{2} - 4)^{2} }{4 + 3x - {x}^{2} }

= \frac{ (3x+x^2-4)(3x-x^2+4) }{(1+x)(4-x)}

= \frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)}

If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give

= { (x-1)(x+4)}

= { x^2+3x-4}

3 0
3 years ago
Read 2 more answers
What is the equation of a line that passes through the points (3,3) and (-3,7)
just olya [345]

Answer:

slope intercept form is y=-2/3x+5

6 0
3 years ago
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