1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexdok [17]
4 years ago
15

Explain how to predict​ y-values using the equation of a regression line.A. Substitute a value of y into the equation of a regre

ssion line and solve for x.B. Use the graph of the regression line to determine the​ x-value that corresponds to the​ y-value for which you are solving.C. Substitute a value of x into the equation of a regression line and solve for y^.D. Substitute the correlation coefficient into the equation and solve for y^
Mathematics
1 answer:
Paul [167]4 years ago
5 0

Answer: C. Substitute a value of x into the equation of a regression line and solve for y

Step-by-step explanation: To predict y values using equation of the regression line, a given value of x is substituted into the equation as there are only two unknowns in the whole regression equation, which are the x value ( independent variable) and the y value (the dependent or predicted variable).

The regression equation is usually of the form:

y = mx + c (linear regression)

Where y = predicted or dependent variable

m = slope or gradient of the regression line

x = independent variable

c = intercept of the line (where it cross the y-axis)

You might be interested in
-x + 8x= -21 find what x is
Reptile [31]

Answer:

-3

Step-by-step explanation:

-x+8x=-21

7x=-21

7x/7=-21/7

x=-3

6 0
3 years ago
I need help answering this. Could someone please explain to me step by step how to do this thank you very much.​
KatRina [158]
<h2>Hope it can help you and please mark me as a brainlist.. </h2>

4 0
3 years ago
Five rectangles are arranged in a row. Each rectangle is half as tall as the previous one. Also, each rectangle’s width is half
olga2289 [7]
Answer: 682

Also, each rectangle’s width is half its height. It can be expressed as
w= 1/2h<span>
The first rectangle is 32cm tall. Then the measurement would be
h=32
w= 1/2h= 16
</span>The first rectangle is 32cm tall and e<span>ach rectangle is half as tall as the previous one. That can be expressed as
h(n)= 32(1/2)^n-1

The area of rectangle is
area(n)= h*w
area(n)=h*</span> (1/2h)= 1/2h ^2
area(n)= 1/2 {32(1/2)^n-1}^2<span>
area(n)= 512(1/2)^2n-2

Then the sum of the 5 rectangle would be:
</span>area(1) + area(2) + area(3) + area(4)+ area(5)
512(1/2)^2(1)-2 + 512(1/2)^2(2)-2 + 512(1/2)^2(3)-2 + 512(1/2)^2(4)-2 +512(1/2)^2(5)-2 = 
512+ 512/4 + 512/16+ 512/ 64 + 512/ 256=
512+ 128 + 32+ 8 + 2= 682
3 0
3 years ago
Read 2 more answers
Ryan needs 1/8 pound of chicken to make one cup of chicken dip. He has 3/4 pound of chicken. Ryan calculated that he can make ex
mamaluj [8]
Yes he is correct because 1/8 x 3 = 3.75.
8 0
3 years ago
Can someone please help me with this?
Irina18 [472]
All the triangles are congruent

because there are two sides and 1 angle that is congruent on all triangles

SAS (theorem?)

hope this helps
5 0
4 years ago
Other questions:
  • a newborn baby sleep can average of 16 hours in 24 hour period what percent of it at time does a newborn baby spend ???
    11·2 answers
  • If 75% of a number is 60, what is 20% of the number
    13·2 answers
  • I don't quite understand this problem: 6+√44/2 (or 6 plus the square root of 44 over 2). I know the answer is 3+√11 (3 plus the
    6·1 answer
  • What is the simplified expression for 5ab+9ab-ab?
    10·2 answers
  • Help pleaasssseeee (use picture) it’ll only take some time out of your day but will be a big impact on my day thank you hope you
    13·1 answer
  • Please help. BRAINLIEST to correct answer!!
    6·1 answer
  • Work out the value of x
    14·2 answers
  • PLS HELP!!!
    5·1 answer
  • Write the expanded form, for 34.75
    15·2 answers
  • Solve these three please, if you're confused, read the instructions.
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!