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3 years ago

A solution containing large amounts of solute in comparison to solvent is what?

1 answer:

6 0

I think this solution is a supersaturated solution. This solution is called us such because the solute in this solution is more than the solvent can dissolve or the ammount of solute exceeds the solutbility of the solute in a particular solvent.

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Definition of distance travelled?

Mekhanik [1.2K]

Answer:

distance traveled is a total length of the path traveled between two positions.

6 0

3 years ago

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Rosa eats a peanut butter sandwich for lunch. Peanut butter contains a lot

shusha [124]

Cmndkdkkdnd djnd dhdbhd s ahah who w baggage wbhebwnwh

4 0

3 years ago

An electron at Earth's surface experiences a gravitational force of magnitude F=(9.11×10−31 kg)⋅(9.8 m/s2). Part A How far away

katrin [286]

Answer:

r = 5,085 m

Explanation:

The force exerted by on the surface of the Earth on an electron is its weight

W = F = 9.11 10⁻³¹ 9.8

W = 8.9 10⁻³⁰ N

The electric force between an electron and a proton is given by Coulomb's Law

Fe = k q₁ q₂ / r²

Fe = - k q² / r²

They ask us that W = Fe

W = k q² / r²

r = √ k q² / W

Let's calculate

r = √ 8.99 10⁹ (1.6 10⁻¹⁹)² /8.9 10⁻³⁰

r = √ 25.86

r = 5,085 m

Let's look for the relationship of this distance with the harmonic distance

R / R_atomic = 5,085 / 10⁻¹⁰

R / R_Atomic = 5 10¹⁰

We see that this distance is 10¹⁰ times the interatomic distance, so the gravitational attraction force is very small at atomic scale

8 0

4 years ago

A whistle of frequency 564 Hz moves in a circle of radius 71.2 cm at an angular speed of 17.1 rad/s. What are (a) the lowest and

trapecia [35]

Answer:

a) $f'=544.66 \textup{Hz}$

b) $f'=584.75 \textup{Hz}$

Explanation:

Given:

Frequency of the whistle, f = 564 Hz

Radius of the circle, r = 71.2 cm = 0.712 m

Angular speed, ω = 17.1 rad/s

speed of source, $v_s$ = rω = 0.712 × 17.1 = 12.1752 m/s

speed of sound, v = 343 m/s

Now, applying the Doppler's effect formula, we have

$f'=f\frac{v\pm v_d}{v\pm v_s}$

where,

$v_d$ = relative speed of the detector with respect to medium = 0

a) for lowest frequency, we have the formula as:

$f'=f\frac{v}{v+v_s}$

on substituting the values, we get

$f'=564\times\frac{343}{343+12.1752}$

$f'=544.66 \textup{Hz}$

b) for maximum frequency, we have the formula as:

$f'=f\frac{v}{v-v_s}$

on substituting the values, we get

$f'=564\times\frac{343}{343-12.1752}$

$f'=584.75 \textup{Hz}$

3 0

3 years ago

On a road trip, a driver achieved an average speed of (48.0+A) km/h for the first 86.0 km and an average speed of (43.0-B) km/h

Bond [772]

A = 15, B = 1
48 + 15 = 63 for the first 86km
43 - 1 = 42 for the remaining 54 km
time = distance/speed
t1 = 86/63 = 1.3651hours
t2 = 54/42 = 1.2857hours
speed = distance/time
s = 140/2.6508
average speed = 52.8km/h

4 0

4 years ago