A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter a

Question

zubka84 [21]

2 years ago

13

A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter a

t a speed of 6.0 meters/second. What is the emf produced?

Physics

1 answer:

GaryK [48] · Answer 1 · 2022-07-12T15:52:49+03:00

GaryK [48]2 years ago

6 0

The emf induced = B*l*v where B is the flux density, l the length of the conductor and v the velocity of the conductor. In the given case B = 0.035 N/amp.meter, l = 0.86 and v = 6 m/sec
emf = 0.035*0.86*6 = 0.1806 v ≈ 0.18 v
choice: D