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Lyrx [107]
3 years ago
13

Describe how you would draw a diagram that shows the electric field between two particles that attract each other.

Physics
2 answers:
Alik [6]3 years ago
7 0

Answer:

You would draw two different circles (the circles represents the charges)  with a plus sign and a negative sign inside. Then draw lines coming out from the circles that bend and connect  to each other in the middle of the two circles. Those lines would represent field lines.

Explanation:

The circles represent the attracted charges. That will represent the lines of force in an electric field extending from one charge to another with the field lines bending and connecting when the two charges are close together.  

Sonja [21]3 years ago
5 0

Since the particles attract each other, I would draw one positive (+) charge close to one negative (–) charge. To show the electric field, I would draw lines coming out in all directions from each charge. Then I would add arrows pointing away from the + charge and pointing toward the – charge. Finally, I would connect the lines coming from the + charge to the ones going toward the – charge to make the loops of the electric field.

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The Moon orbits the Earth in an approximately circular path. The position of the moon as a function of time is given by: x(t) =
Aleks [24]

Answer: Average Velocity = - 643.42 i + 512.66 j m/s

Magnitude = 822.7 m/s

Direction = 141.45°

Explanation:

r = 3.84 x 10^8 m

w = 2.46 x 10^-6 rad/s

Formula for Average velocity = displacement / time

at t = 0

x(0) = r

y(0) = 0

at t = 8.45 days

= 8.45 x 24 x 3600 s =730080 sec

w t = 2.46 x 10^-6 x 730080 = 1.80 rad Or 102.90°

xf = r cos(w t) = - 0.2233r

yf = r sin(w t) = 0.9747r

Displacement = (xf - x0)i + (yf - y0)j = -1.2233r i + 0.9747r j

<v> = dispalcement / t = (-1.2233r i + 0.9747r j ) / (730080 s )

= - 643.42 i + 512.66 j m/s

Magnitude

= sqrt(643.42^2 + 512.66^2)

= 822.7 m/s

Direction

= 180 - tan^-1(512.66 / 643.42)

= 141.45°

8 0
3 years ago
Read 2 more answers
Work and Energy
Sergeeva-Olga [200]

a) W_1 = 2332 J, W_2= 2332 J

The work done by the student in each trial is equal to the gravitational potential energy gained by the student:

W=mg\Delta h

where

m = 68 kg is the mass of the student

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h is the gain in height of the student

For the first student, \Delta h = 3.5 m, so the work done is

W_1 = (68)(9.8)(3.5)=2332 J

The second student runs up to the same height (3.5 m), so the work done by the second student is the same:

W_2 = (68)(9.8)(3.5)=2332 J

2) P_1 = 204.6 W, P_2 = 274.4 W

The power exerted by each student is given by

P=\frac{W}{t}

where

W is the work done

t is the time taken

For the first student, W_1 = 2332 J and t=11.4 s, so the power exerted is

P_1 = \frac{W_1}{t_1}=\frac{2332 J}{11.4 s}=204.6 W

For the second student, W_2 = 2332 J and t=8.5 s, so the power exerted is

P_2 = \frac{W_2}{t_2}=\frac{2332 J}{8.5 s}=274.4 W

5 0
3 years ago
Tarzan swings back and forth on a
WARRIOR [948]

Answer:

Considering Tarzan as a point mass at point L and using the equation for a simple pendulum:

P = 2 pi (L / g)1/2

P^2 = 4 pi^2 L / g

L = g P^2 / (4 pi^2) = 9.8 m/s^2 * 7.27^2 s^2 / (4 pi^2) = 13.1 m

4 0
3 years ago
A quantity of gas is contained in a sealed container of fixed volume. The temperature of the
Alchen [17]

Answer:

If the Kelvin temperature of a gas is increased, the volume of the gas increases. This can be understood by imagining the particles of gas in the container moving with a greater energy when the temperature is increased.

Explanation:

If you heat a gas you give the molecules more energy so they move faster. This means more impacts on the walls of the container and an increase in the pressure. Conversely if you cool the molecules down they will slow and the pressure will be decreased.

To calculate a change in pressure or temperature using Gay Lussac's Law.

6 0
3 years ago
calcular la longitud de un péndulo que oscila a 10 Hz en santa fe de bogota, sabiendo que en esta ciudad la aceleracion de la gr
cricket20 [7]

Answer:

L=2.48*10^{-3} m

Explanation:

The period equation for a pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}}

and we know that T = 1/f, where f is the frequency, so we will have:

\frac{1}{f}=2\pi \sqrt{\frac{L}{g}}

Now, we just need to solve this equation for L.

\frac{1}{2\pi f}=\sqrt{\frac{L}{g}}

L=\frac{g}{(2\pi f)^{2}}

  • g is the gravity in Bogota (g=9.78 m/s^{2})
  • f is 10 Hz
  • L is the lenght of the pendulum

L=\frac{9.78}{(2\pi*10)^{2}}

L=2.48*10^{-3} m

I hope it helps you!

5 0
3 years ago
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