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Verdich [7]
2 years ago
11

The science of classifying and naming organisms based on their different characteristics is called ______________.

Physics
2 answers:
Fofino [41]2 years ago
8 0

Answer:

Biology

Explanation:

Hopethis helps!

Oksanka [162]2 years ago
3 0

Answer:

Taxonometric

Explanation:

A biologist named Carolus Linnaeus started this naming system. 

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Is there proof of the existence of God and Satan?If so what proof?
ivolga24 [154]
Religiously it has been proved that God exist and even satan exist
scientist does not believe God exist.The big bang theory is a theory that postulated that a big bang occur when and everything but my proverb says "in a film there is always behind the scene" if God doesnt exist who created mountains,hills,rivers,oceans,man,animal,spirit and if satan doesnt exist why does hell exist but if God doesnt exist why is it in grammar law to use capital letter for God
but my advise for you is to ask God to show you if He truly exist

3 0
3 years ago
point) A circular swimming pool has a diameter of 12 m. The circular side of the pool is 3 m high, and the depth of the water is
Sergio [31]

Answer:

(a) 86.65 J

(b) 149.65 J

Solution:

As per the question:

Diameter of the pool, d = 12 m

⇒ Radius of the pool, r = 6 m

Height of the pool, H = 3 m

Depth of the pool, D = 2.5 m

Density of water, \rho_{w} = 1000\ kg//m^{3}

Acceleration due to gravity, g = 9.8\ m/s^{2}

Now,

(a) Work done in pumping all the water:

Average height of the pool, h = \frac{H + D}{2}

h = \frac{3 + 2.5}{2} = 2.75\ m

Volume of water in the pool, V = \pi r^{2}h = \pi \times 6^{2}\times 2.75 = 311.02\ m^{3}

Mass of water, m_{w} = \frac{\rho_{w}}{V}

m_{w} = \frac{1000}{311.02} = 3.215\ kg

Work done is given by the potential energy of the water as:

W = m_{w}gh = 3.215\times 9.8\times 2.75 = 86.65\ J

(b) Work done to pump all the water through an outlet of 2 m:

Now,

Height, h = 2.75 + 2 = 4.75

Work done,W = m_{w}gh = 3.215\times 9.8\times 4.75 = 149.65\ J

7 0
2 years ago
Why do the planets appear in different locations in the night sky while the pattern of stars in a constellation stays the same?
Goshia [24]
I'm sure you've noticed that an airplane high in the sky, far away
from you, looks like it's moving very slowly.  At the same time,
somebody passing you on a skateboard whizzes past you at
high speed.  The farther away something is from you, the slower
it appears to move.

The nearest star outside the solar system is almost 32 thousand times
as far away from us as the farthest visible planet (Saturn) is, and all of the
other stars are farther than that. 

That's why you have to wait a few thousand years before you notice
that the shape of a constellation has changed.

To put it a slightly different way . . . Everything is in motion.  The motion is
more noticeable for nearby things, and less noticeable for farther-away things. 
Objects within our solar system are the only ones near enough so that a human
lifetime is a long enough period in which to notice the change in their position.
Even Pluto moves less then 1.5° against the 'background' stars in a whole year.

This all makes me feel small.  How about you ?
7 0
3 years ago
Read 2 more answers
A space shuttle sits on the launch pad for 2.0 minutes, and then goes from rest to 4600 m/s in 8.0 minutes. Treat its motion as
SpyIntel [72]

Answer:

a.) a = 0 ms⁻²

b.) a = 9.58 ms⁻²

c.) a = 7.67 ms⁻²

Explanation:

a.)

    Acceleration (a) is defined as the time rate of change of velocity

                       a = \frac{v_{2} - v_{1} } {t}  

Given data

 Final velocity = v₂ = 0 m/s

 Initial velocity = v ₁ = 0 m/s

  As the space shuttle remain at rest for the first 2 minutes i.e there is no change in velocity so,

                 a = 0 ms⁻²

b.)

     Given data

As the space shuttle start from rest, So initial velocity is zero

    Initial velocity = v₁ = 0 ms⁻¹

    Final velocity  = v₂ = 4600 ms⁻¹

     Time = t = 8 min = 480 s

By the definition of Acceleration (a)

             a = \frac{v_{2} - v_{1} } {t}  

             a = \frac{4600 - 0 } {480}

                     a = 9.58 ms⁻²

c.)

    Given data

As the space shuttle is at rest for first 2 min then start moving, So initial velocity is zero

    Initial velocity = v₁ = 0 ms⁻¹

    Final velocity  = v₂ = 4600 ms⁻¹

     Time = t = 10 min = 600 s

By the definition of Acceleration (a)

             a = \frac{v_{2} - v_{1} } {t}  

             a = \frac{4600 - 0 } {600}

                     a = 7.67 ms⁻²

8 0
3 years ago
10 PTS! HELP!<br> If you have a mass of 47 kg on Earth, determine your mass on the moon.
Marta_Voda [28]

The mass would be the same

47kg on the moon as well

6 0
2 years ago
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