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Ivahew [28]
3 years ago
11

Which number is greatest? 6.23 times 10 Superscript 12 6.23 times 10 Superscript 8 6.23 times 10 Superscript negative 6 6.23 tim

es 10 Superscript 3
Mathematics
1 answer:
ANEK [815]3 years ago
4 0
6.23 times 10 superscript 12
It shows the 10 has been multiplied by itself thrice
Please mark as brainliest
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3.2-4d=2.3d+3 i need the answer
borishaifa [10]

Answer:

d=0.031746

Step-by-step explanation:

1. Add 4d to both sides: 3.2=2.3d+3+4d

2. Simplify 2.3d +3+ 4d to 6.3d+3: 3.2=6.3d+3

3. Subtract 3 from both sides: 3.2-3=6.3d

4. Simplify 3.2-3 to 0.2: 0.2-6.3d

5. Divide both sides by 6.3: 0.2/6.3=d

6. Simplify 0.2/6.3 to 0.031746: 0.031746=d

7. Switch sides: d=0.031746

Hope this helped!

7 0
3 years ago
Lee is thinking of two Numbers,the product is 18. the quotient is 2
defon
X, y - the numbers

The product is 18.
xy=18

The quotient is 2.
\frac{x}{y}=2 \ \ \ |\times y \\
x=2y

Substitute 2y for x in the 1st equation:
2y \times y=18 \\
2y^2=18 \ \ \ |\div 2 \\
y^2=9 \\
y=\pm \sqrt{9} \\
y=3 \ \lor \ y=-3 \\ \\
x=2y \\
x=2 \times 3 \ \lor \ x=2 \times (-3) \\
x=6 \ \lor \ x=-6 \\ \\
(x,y)=(6,3) \hbox{ or } (x,y)=(-6,-3)

The numbers are 6 and 3 or -6 and -3.
6 0
3 years ago
Read 2 more answers
A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate
neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:  

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate  munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

C-2=\frac{1}{11}*(C+D-2)...(1)

We are also told if he instead added 4  glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

C=\frac{1}{7}*(C+D+4)...(2)

Upon substituting C's value from equation (2) in equation (1) we will get,

\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)

Let us have a common denominator on right side of equation.

\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)

\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)

Multiplying both sides of our equation by 7, we will get,

7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)

C+D-10=\frac{7}{11}*(C+D-2)  

Multiplying both sides of our equation by 11, we will get,

11*(C+D-10)=11*\frac{7}{11}*(C+D-2)  

11*(C+D-10)=7*(C+D-2)

11C+11D-110=7C+7D-14

11C-7C+11D-7D=-14+110  

4C+4D=96

4(C+D)=96  

(C+D)=\frac{96}{4}

(C+D)=24

Therefore, the total number of Munchkins in original box is 24.

3 0
3 years ago
What is the perimeter of a triangle with side lengths of 9, 12, and 4x?
ludmilkaskok [199]
The answer is 21 + 4x.


You find this answer by adding up all the sides.
9+12+4x= 21+4x ... you don't add 4x because it has a variable that we do not know of the value.
3 0
4 years ago
13+(w)/(7)=-18<br><br> step by step?
kotykmax [81]

w in (-oo:+oo)

w/7+13 = -18 // + 18

w/7+13+18 = 0

1/7*w+31 = 0 // - 31

1/7*w = -31 // : 1/7

w = -31/1/7

w = -217

w = -217


3 0
3 years ago
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