Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.
If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:
E[2<em>X </em>² - <em>Y</em>] = 2 E[<em>X </em>²] - E[<em>Y</em>]
Or, if you're given the expectation and variance of <em>X</em>, you have
Var[<em>X</em>] = E[<em>X</em> ²] - E[<em>X</em>]²
→ E[2<em>X </em>² - <em>Y</em>] = 2 (Var[<em>X</em>] + E[<em>X</em>]²) - E[<em>Y</em>]
Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.
Answer:
C
Step-by-step explanation:
∠ TUL + ∠ LUV = ∠ TUV , substitute values
x + 16 + 11x = 172 , that is
12x + 16 = 172 ( subtract 16 from both sides )
12x = 156 ( divide both sides by 12 )
x = 13 → C
A repeating decimal is one that essentially goes on forever. A terminating decimal is one that has an end, therefore a definite value.
The fraction 1/3 is a repeating decimal, because when you divide 1 by 3, you get .333333 (to infinity). To show that something is repeating, draw a bar (or line) above the number that is repeating, in this case, 3.
The fraction 1/4 is a terminating decimal. Like the one above, when you divide 1 by 4, you get a fraction. In this case, it is .25, which does not repeat.
The fractions are there just to show you how you could get to either, but your terminating decimal is .25, and your repeating decimal is .3 (but with a line over the 3 if possible).
Answer:
x=-15
x=6
x=3
x=-21
Step-by-step explanation:
