Josh is incorrect, he did not examine the expression correctly, therefore his answer was wrong.
volume cylinder
=3.14×3^2×5
=141.3 cubic inches
volume sphere
=4/3×3.14×3^3
=113.04 cubic inches
difference between volume of cylinder and sphere
=141.3-113.04
=28.26 cubic inches
Answer:
They have the same domain and range
Step-by-step explanation:
Although they are different equations, they both have a domain of
[0,∞)
and a range of
[0,∞)
9514 1404 393
Answer:
1 < x < 29
Step-by-step explanation:
The triangle inequality requires the sum of the two shortest sides exceed the longest side.
<u>When x and 14 are the shortest</u>:
x + 14 > 15
x > 1
<u>When 14 and 15 are the shortest</u>:
14 +15 > x
29 > x
Then the requirement for the length of x is ...
1 < x < 29
_____
<em>Additional comment</em>
The length of the third side of a triangle can be between the difference and sum of the two given sides.
Answer:
The horizontal distance from the center is 49.3883 feet
Step-by-step explanation:
The equation of an ellipse is equal to:
![\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7Ba%5E%7B2%7D%20%7D%20%2B%5Cfrac%7By%5E2%7D%7Bb%5E%7B2%7D%20%7D%20%3D1)
Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.
Then, replacing a by 106/2 and b by 33.9, we get:
![\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7B53%5E%7B2%7D%20%7D%20%2B%5Cfrac%7By%5E2%7D%7B33.9%5E%7B2%7D%20%7D%20%3D1%5C%5C%5Cfrac%7Bx%5E2%7D%7B2809%7D%20%2B%5Cfrac%7By%5E2%7D%7B1149.21%7D%20%3D1)
Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:
![\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7B2809%7D%20%2B%5Cfrac%7By%5E2%7D%7B1149.21%7D%20%3D1%5C%5C%5Cfrac%7Bx%5E2%7D%7B2809%7D%20%2B%5Cfrac%7B12.3%5E2%7D%7B1149.21%7D%20%3D1%5C%5C%5C%5C%5Cfrac%7Bx%5E2%7D%7B2809%7D%3D1-%5Cfrac%7B12.3%5E2%7D%7B1149.21%7D%5C%5C%5C%5Cx%5E%7B2%7D%20%3D2809%280.8684%29%5C%5Cx%3D%5Csqrt%7B2809%280.8684%29%7D%5C%5Cx%3D49.3883)
So, the horizontal distance from the center is 49.3883 feet