Answer:
160 miles
Step-by-step explanation:
Company A form $130 a day plus $0.30 per mile
Company A = 130 + 0.30x
Company B charges $50 a day plus $0.80 per mile
Company B = 50 + 0.80x
Where,
x = number of miles
Equate the cost of company A and company B
130 + 0.30x = 50 + 0.80x
Collect like terms
130 - 50 = 0.80x - 0.30x
80 = 0.50x
Divide both sides by 0.50x
x = 80 / 0.50
= 160
x = 160 miles
The number of miles in a day at which the rental costs for Company A and Company B are the same is 160 miles
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<span>The best and most correct answer among the choices provided by the question is FALSE.</span><span>
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<span>Hope my answer would be a great help for you.</span></span>
Answer:
Here is the rule: when a and b are not negative
√(ab) = √a × √b
Example: simplify √8
√8 = √(4×2) = √4 × √2 = 2√2
(Because the square root of 4 is 2)
In other words 2 x 4 = 8 = √2 x 4 but 4 can be simplified more (2 x 2) so 2 (previous 4) moves to the left of the square root leaving 2√2
To simplify a square root: make the number inside the square root as small as possible (but still a whole number)
or you can use a simplifying square root calculator.
I remember answering the same question, but you didn't attach any photos. But I remember that the answer is the first one.
I hope I helped. Stay safe and God bless!
- Eli <3
105 different outfits can wear on an individual day
<em><u>Solution:</u></em>
I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work
To find: Number of different outfits can I wear on an individual day
First he has to decide on a pair of pants and he has 5 different choices
For each of those choices he has a choice of 7 different button down shirts, so that gives him 5 x 7 = 35 different pant/shirt combinations
For each of those 35 different pant/shirt combinations, he has 3 pairs of shoes he could select, so altogether he has 35 x 3 = 105 different outfits
In short we can say,
different outfits = 7 x 5 x 3 = 105
So there 105 different outfits can wear on an individual day
