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vovangra [49]
4 years ago
10

Whats the slope. review but i forgot (//_^)​

Mathematics
1 answer:
Masja [62]4 years ago
7 0

Answer:

slope = 1

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (2, 5) and (x₂, y₂ ) = (- 5, - 2)

m = \frac{-2-5}{-5-2} = \frac{-7}{-7} = 1

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An ecological group suspects lobsters are consuming dangerous levels of mercury in a region of the world. Dangerous levels of me
Crank

Part A: 5 out 25 lobsters have dangerous levels of mercury

Part B: the 95% confidence interval is given by (4.45, 5.65)

since everything is given all I had to do is find the critical value which can be found from the resource packet = 2.064

Using the formula we find 5.05+-2.064*1.45/5 = ( 4.45,5.65)

For this case, we have 95% of confidence that the true mean for the average number of lobsters with dangerous levels of mercury is between 4.45,5.65

5 0
3 years ago
a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s
Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

                         P.Q. = \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s^{2}  = sample variance = 97^{2} = 9409

              n = sample of boxes = 15

           \sigma^{2}  = population variance

<em>Here for constructing 95% confidence interval we have used chi-square test statistics.</em>

So, 95% confidence interval for the population variance, \sigma^{2} is ;

P(5.629 < \chi^{2}__1_4 < 26.12) = 0.95  {As the critical value of chi-square at 14

                                         degree of freedom are 5.629 & 26.12}  

P(5.629 < \frac{(n-1)s^{2} }{\sigma^{2} } < 26.12) = 0.95

P( \frac{5.629 }{(n-1)s^{2} } < \frac{1}{\sigma^{2} } < \frac{26.12 }{(n-1)s^{2} } ) = 0.95

P( \frac{(n-1)s^{2} }{26.12 } < \sigma^{2} < \frac{(n-1)s^{2} }{5.629 } ) = 0.95

<u><em>95% confidence interval for</em></u> \sigma^{2} = [ \frac{(n-1)s^{2} }{26.12 } , \frac{(n-1)s^{2} }{5.629 } ]

                                                  = [ \frac{14 \times 9409 }{26.12 } , \frac{14 \times 9409 }{5.629 } ]

                                                  = [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

6 0
3 years ago
Let f(x)=2x^2+7x-5 and g(x)=-8x^2-3x+5 what is g(x)+f(x)
ser-zykov [4K]
F(x) = 2x² + 7x - 5
g(x) = -8x² - 3x + 5
g(x) + f(x) = -8x² - 3x + 5 + 2x² + 7x - 5 = - 6x² + 4x

Answer: -6x² + 4x
4 0
3 years ago
Read 2 more answers
Look at the table showing prices of orange juice. Which is the best value for buying orange juice?
ValentinkaMS [17]

Answer:

we need to see the chart so we can answer the question sir or ma'am

Step-by-step explanation:

5 0
4 years ago
Angela asked each member of her class if they ever been to six flags over Georgia the class consists of 10 males and 14 females.
Feliz [49]

Answer:

2 male students didn't visit six falgs.

Step-by-step explanation:

Hello!

You have the following information:

The class has 10 male students and 14 female students.

From the females, 8 visited six flags over Georgia.

And from the total of students of class 16 visited the six flags over Georgia.

Using this information you have to calculate the number of male students that did not visit six flags.

First step: Calculate the number of male students that visited six flags.

The total of students that visited is 16 from those 8 are female then 16 - 8 = 8 male students visited six flags.

Second step: Calculate the number of students that didn't visit it.

From the total of male students in the class, 8 visited six flags so 10 - 8 = 2 male students didn't visit six flags over GA.

I hope this helps!

7 0
3 years ago
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