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bogdanovich [222]
3 years ago
14

In general, in what type of solvent (non-polar, moderately polar, or highly polar) are polar solutes most soluble? Explain why.

Chemistry
1 answer:
tia_tia [17]3 years ago
5 0

Answer:

  • In general, polar solutes are most soluble in highly polar solvents.

Explanation:

The general rule is "like dissolves like" which means that <em>polar solvents </em>dissolve polar (or ionic) <em>solutes</em> and <em>non-polar solvents</em> dissolve non-polar solutes.

In order for a solvent dissolve a solute, the strength of the interacttion (force) between the solute and the solvent units (atoms, molecules, or ions) must be stronger than the strength of the forces that keep together he particles of the pure substances (known as intermolecular forces).

Since the nature of the interactions between the units are electrostatic, the more polar is the solvent the better it will be able to attract and surround the solute particles, keeping them separated and in solution. That mechanism explains why polar solutes will be most soluble in highly polar solvents.

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Which statements are true?
schepotkina [342]

Explanation:

  • Evaporation is defined as a process in which liquid state of water is changing into vapor state.

So, we need to break the bonds of liquid substance in order to convert it into vapor state. And, energy is absorbed for breaking of bonds which means that evaporation is an endothermic process.

Hence, the statement evaporation of water is an exothermic process is false.

  • When a hydrocarbon reacts with oxygen and leads to the formation of carbon dioxide and water then this type of reaction is known as combustion reaction.

A combustion reaction will always release heat energy. Hence, combustion reaction is exothermic in nature.

  • When energy is transferred as heat from the surroundings to the system then it means energy is being absorbed by the system. And, absorption of heat is an endothermic process for which \Delta H is positive.
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Hence, for an exothermic process value of \Delta H is negative.

Thus, we can conclude that statements which are true are as follows.

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