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Andreas93 [3]
3 years ago
8

How many moles of KNO3 will be required to prepare 8.0L of 1.40 M KNO3?

Chemistry
1 answer:
blagie [28]3 years ago
6 0

Answer:

11.2 moles of KNO3 will be required to prepare 8.0 L of 1.40 M KNO3

Explanation:

To answer this question, we need an understanding of the units of the term called molarity.

1.40M KNO3 means that there are 1.4 moles per dm^3 or per liter of the solution.

Now, since there are 1.4 moles in 1 liter

x moles will be present in 8.0 liters

Thus, mathematically;

x * 1 = 8 * 1.4

x = 11.2 moles

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SVEN [57.7K]

Answer:

The answer is

<h2>250 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of object = 25 mL

Density = 10 g/mL

The mass of the object is

mass = 25 × 10

We have the final answer as

<h3>250 g</h3>

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