Is the sentence How tall is a oak tree? a statistical question?
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If we look at the series, one third of the current term gives the numerical value of the next term.
If we need to express it algebraically, we can write the following equation.
Therefore, our common multiplier can be found as follows. Because this sequence is a geometric sequence.
In geometric sequences, any term can be written in terms of the first term. Below is an example.
Since we know the numerical values of the first term and the common factor of the series, we can easily find the seventh term.
We have that
7x^2 + 4x - 8 = 14-----------------> 7x²+4x-22=0
Step 1
Solving<span> a </span><span>second degree equation
</span>x1=[-b+√(b²-4ac)]/2a
x2=[-b-√(b²-4ac)]/2a
a=7
b=4
c=-22
then
x1=[-4+√(4²-4*7*(-22))]/(2*7)-----------> [-4+√(632)]/(14)
x1=-(-4+25.14)/14=1.51
x2=[-4-√(4²-4*7*(-22))]/(2*7)-----------> [-4-√(632)]/(14)
x2=-(-4-25.14)/14=-2.08
the solutions of the system is
x1=1.51
x2=-2.08
<span>to check the result
</span>
using a graph tool
see the attached figure
the answer is
the numerical expressions is
x1=[-b+√(b²-4ac)]/2a
x2=[-b-√(b²-4ac)]/2a
7x^2 + 4x - 8 = 14-----------------> 7x²+4x-22=0
Step 1
Solving<span> a </span><span>second degree equation
</span>x1=[-b+√(b²-4ac)]/2a
x2=[-b-√(b²-4ac)]/2a
a=7
b=4
c=-22
then
x1=[-4+√(4²-4*7*(-22))]/(2*7)-----------> [-4+√(632)]/(14)
x1=-(-4+25.14)/14=1.51
x2=[-4-√(4²-4*7*(-22))]/(2*7)-----------> [-4-√(632)]/(14)
x2=-(-4-25.14)/14=-2.08
the solutions of the system is
x1=1.51
x2=-2.08
<span>to check the result
</span>
using a graph tool
see the attached figure
the answer is
the numerical expressions is
x1=[-b+√(b²-4ac)]/2a
x2=[-b-√(b²-4ac)]/2a