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weeeeeb [17]
3 years ago
10

Solving system by substitution x=3y+11, 2x-3y=16

Mathematics
2 answers:
grin007 [14]3 years ago
5 0
Input 3y+11 for x

2(3y+11)-3y=16
6y+22-3y=16
3y= -6
Divide by 3 to isolate y
y=-2

Now for x....

x=3(-2)+11
=-6+11
=5
x=5

Coordinates (5,-2)
victus00 [196]3 years ago
4 0
1. You plug the x equation in the nest on. 2(3y+11)-3y=16.

2. You then simplify it. 6y+22-3y=16

3. You simplify it more. 3y+22=16.

4. Next you subtract 22 from each side. 3y=-6.

5. Divide both sides by 3. y=-2

6. Then substitute y for the first equation. x=3(-2)+11

7. Next you simplify. x=-6+11

8. Simplify more. x=5

9. You get your results. x=5 and y=-2
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22

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6 0
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Answer is B
****************************************
6 0
3 years ago
(2.5×10^−10)(7×10^−6)
Nataly [62]
<span>(2.5×10^−10)(7×10^−6) 
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<span>B. 1.75×10^−15 </span>
6 0
3 years ago
One of the legs of a right triangle measures 6 cm and its hypotenuse measures 8 cm. Find the measure of the other leg. If necess
Vika [28.1K]
Well, this is a Pythagorean theorem problem. A^2 + B^2 = C^2, where C^2 is equal to the hypotenuse. 8 squared equals 64, so c^2 = 64 cm. The other leg can be represented by A^2, which is 36 cm. 36 + ? = 64. 64 - 36 = 28, so B^2 equals 28. Now, to find the measurement of the other leg, we need the square root of 28. The square root of 28 is 5.3 cm.

Your final answer is 5.3 cm.
8 0
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Distribute:

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You can't really find what n is I don't think, because you have 2 unknown variables n and A(n).

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