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3 years ago

Solving system by substitution x=3y+11, 2x-3y=16

2 answers:

5 0

Input 3y+11 for x

2(3y+11)-3y=16
6y+22-3y=16
3y= -6
Divide by 3 to isolate y
y=-2

Now for x....

x=3(-2)+11
=-6+11
=5
x=5

Coordinates (5,-2)

victus00 [196]3 years ago

4 0

1. You plug the x equation in the nest on. 2(3y+11)-3y=16.

2. You then simplify it. 6y+22-3y=16

3. You simplify it more. 3y+22=16.

4. Next you subtract 22 from each side. 3y=-6.

5. Divide both sides by 3. y=-2

6. Then substitute y for the first equation. x=3(-2)+11

7. Next you simplify. x=-6+11

8. Simplify more. x=5

9. You get your results. x=5 and y=-2

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3 years ago

Read 2 more answers

How do you find the arctan 4/3 ? (Without a calculator)

Soloha48 [4]

If arctan 4/3 = the tangent of that angle will be 4/3 , opposite 4 over adjacent 3

Now, you only have to take the sin of that angle it's opposite 4 over hypotenuse 5.

You will get that the answer is 4/5

hope this helps

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3 years ago