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elena-14-01-66 [18.8K]
3 years ago
9

Which of the following statements is false?

Mathematics
1 answer:
vodomira [7]3 years ago
6 0
A. The some of two rational numbers is always rational .
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A triangle has one angle that measures 70 degrees, one angle that measures 42 degrees, and one angle that measures 68 degrees. W
Leto [7]

Answer:

Scalene Acute Triangle

Step-by-step explanation:

The triangle above is an <em>"acute triangle"</em> because the measurement of each angle is <em>less than 90°</em>. However, there are three types of acute triangle and these are: <em>Equilateral Acute Triangle, Isosceles Acute Triangle and Scalene Acute Triangle.</em>

When all the angles have the same measurement of less than 90°, then it is an Equilateral Acute Triangle. If only two angles have the same measurement, it is an Isosceles Acute Triangle. If <u><em>none of the angles are the same </em></u>but all are less than 90°, which also means that the<u><em> sides are also unequal</em></u>, then it is an Scalene Acute Triangle.

The triangle above has <em>different angle measurements of less than 90°</em>. Therefore, it is an Scalene Acute Triangle.

6 0
3 years ago
HELP ME
Alex777 [14]

Answer:

<em>Trapezoid ABCD ​ was reflected across the y-axis and then translated 7 units up.</em>

<em />

6 0
4 years ago
A retailer (GameStop, Target, or other stores) will receive 23% of the sale price of a video game. If a retailer sells a video g
prohojiy [21]

Answer:

$13.80

Step-by-step explanation:

23% of 60 = .23 x 60

5 0
3 years ago
What is a word problem for this equation -2(-3.5)
Fiesta28 [93]
Every hand you lose in poker cost you -3.50. How much do you make if you win two hands. 
4 0
3 years ago
Descried how to derive the quadratic formula from a quadratic equation in standard form
Aleks [24]

Answer:

The standard form of a quadratic equation is:

ax^2+bx+c=0, a\neq 0

Quadratic Formula Derivation:

ax^2+bx+c=0\\

$x^2+\frac{b}{a}x+\frac{c}{a} =0 $

$x^2+\frac{b}{a}x = -\frac{c}{a}$

Completing the Square:

$x^2+\frac{b}{a}x +\frac{b^2}{4a^2} = \frac{b^2}{4a^2}-\frac{c}{a}$

$  ( x+\frac{b}{2a} )^2 =  \frac{b^2-4ac}{4a^2}  $

Square Root property:

$x+\frac{b}{2a}  = \pm \sqrt{ \frac{b^2-4ac}{4a^2}}   $

$x  = -\frac{b}{2a} \pm  { \frac{\sqrt {b^2-4ac}}{2a}}   $

$x  =  \frac{-b\pm\sqrt{b^2-4ac}} {2a}  }   $

8 0
3 years ago
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