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Ahat [919]
3 years ago
14

Given that ΔPQR is similar to ΔPTS, which statement MUST be true? A) m∠PST = m∠QPR B) m∠TPS = m∠RPQ C) m∠SPT = m∠PTS D) m∠PRQ =

m∠PTS
Mathematics
2 answers:
Andrei [34K]3 years ago
8 0

Answer: B, angle TPS is equal to angle RPQ. I have taken the assement and it is the correct answer.

Step-by-step explanation:

galina1969 [7]3 years ago
7 0

Answer:

The correct option is B.

Step-by-step explanation:

Two triangle are similar if their corresponding sides are in the same proportion or the corresponding angles are same.

It is given that the ΔPQR is similar to ΔPTS. It means all corresponding angles are same.

\angle R=\angle S

\angle Q=\angle T

\angle P=\angle P

Angle P can be defined as

\angle QPR=\angle TPS

\angle RPQ=\angle TPS

Therefore option B is correct.

\angle PST\neq\angle QPR

\angle SPT\neq\angle PTS

\angle PRQ\neq\angle PTS

Therefore option A, C and D are incorrect.

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Use cylindrical coordinates. Find the volume of the solid that lies within both the cylinder x2 y2
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Answer:

hello your question is incomplete here is the complete question

Use cylindrical coordinates Find the volume of the solid that lies within both the cylinder x^2 + y^2=16 and the sphere x^2 + y^2 + Z^2= 81

Answer : \frac{4 \pi }{3} [729 - 65\sqrt{65} ]

Step-by-step explanation:

The given data

cylinder  = x^2 + y^2 = 16

sphere = x^2 + y^2 +z^2 = 81

from the given data the solid is symmetric around the xy plane hence we will calculate half the solid volume above the plane then  multiply the sesult by 2

Note : we are restricting our attention to the cylinder  x^2 + y^2 = 16 and also finding the volume inside the sphere which gives bound on the z-coordinate as well

the r parameter goes from 0 to 4

ATTACHED IS THE REMAINING PART OF THE SOLUTION

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4 years ago
2. (For this problem, leave your answers in Combinatorics format – do NOT simplify). A conference is being held that faculty mem
SSSSS [86.1K]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

please find the complete question in the attached file.

female = 23  and male = 19 faculty members

Randomly selected member are = 6

In point 1:

The Probability to equally selecting men and women:

= \frac{(23C3+19C3)}{42C6}

In point 2:

The Probability of selecting at least 4 men:

= \frac{((19C4 \times 23C2)+(19C5 \times 23C1)+(19C6))}{42C6}

In point 3:

The probability in which no women are chosen implies that 6 selected members are from 23 women:

= \frac{23C6 }{42C6}

In point 4:

The Probability in which no more than 4 women are selected:

\frac{((19C6)+(23C1 \times 19C5)+(23C2 \times 19C4)+(23C3 \times 19C3)+(23C4 \times 19C2))}{42C6}

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3 years ago
A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is
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2/5 * P(2nd red) = 1/7
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P(2nd Red) = 5/14 or D
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egoroff_w [7]
Follow the order of operations!!
1. Parentheses
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3 years ago
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Answer:

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