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Citrus2011 [14]
3 years ago
6

Find the value of y for a given value of x, if y varies directly with x. If y = 2.52 when x = 8.4, what is y when x = 2.7?  (1 p

oint) 9 –9 0.81 –0.81
Mathematics
2 answers:
Levart [38]3 years ago
5 0

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form (y/x)=k\ or\ y=kx

in this problem we have

y = 2.52\ when\ x = 8.4

so

<u>Find the value of the constant k</u>

(y/x)=k

substitute

k=(2.52/8.4)

k=0.3

the equation is equal to

y=0.3x

<u>Find the value of y when x=2.7</u>

substitute the value of x in the equation

y=0.3*2.7

y=0.81

therefore

<u>the answer is</u>

0.81


Gwar [14]3 years ago
4 0
 <span>8.4/2.52 = 2.7/y 
cross multiply: 
8.4y = 6.80 
y = 6.80/8.4 =  choice (D) </span>
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