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SVETLANKA909090 [29]
3 years ago
12

A rectangle is 9 ft long and 40 in. wide. What is its area in square feet?

Mathematics
2 answers:
Bad White [126]3 years ago
7 0

Answer:

29.97 square feet

Step-by-step explanation:

Given

The length of rectangle = 9 ft

The width of rectangle = 40 in

We have to bring the length and width in same unit. As the area is required in square feet so we will convert width in feet

The width will be divided by 12 to be onverted into feet

So,

Width = 40/12 = 3.33 feet

Now

Area = Length * width

= 9 * 3.33

= 29.97 square feet ..

Snezhnost [94]3 years ago
4 0

<u>Answer:</u>

Area of rectangle = 30 square feet

<u>Step-by-step explanation:</u>

We are given that a rectangle is 9 feet long and 40 inches wide and we are to find its area in square feet.

For this, we will covert the width of the rectangle to feet and then find the area.

We know that:

\frac{1 foot}{x} =\frac{12 inches}{40}\\x=3.3 feet

So width in feet is 3.3 feet.

Area of rectangle = 9 \times 3.33 = 30 square feet

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Answer:

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

-4x + 16 = y

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<u>Step 2: Solve for </u><em><u>x</u></em>

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Iteru [2.4K]

Answer:

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Step-by-step explanation:

* Lets explain how to solve the problem

- If a line bisects another line that means the point of intersection

 divides the second line into two equal parts

∵ EF bisects CD at G

∴ CG = GD

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∴ 7x - 13 = 5x - 1

* Lets solve the equation

∵ 7x - 13 = 5x - 1

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- Substitute the value of x to find EF

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∴ EF = 32

∵ GF = 13

- Substitute the values of EF and GF in the equation of EF

∴ 32 = EG + 13

- Subtract 13 from both sides

∴ 19 = EG

* EG = 19

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4 years ago
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