A rectangle is 9 ft long and 40 in. wide. What is its area in square feet?
2 answers:
<u>Answer:</u>
Area of rectangle = 30 square feet
<u>Step-by-step explanation:</u>
We are given that a rectangle is 9 feet long and 40 inches wide and we are to find its area in square feet.
For this, we will covert the width of the rectangle to feet and then find the area.
We know that:
So width in feet is 3.3 feet.
Area of rectangle = = 30 square feet
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Answer:
y = - 4x + 13
Step-by-step explanation:
In order to do this problem you would need a whole new equation, but you will use what is given to you:
instead of going with:
x - 4y = 20
Turn it into y = mx + b form, also known as slope-intercept form:
x - 4y = 20
-x = -x
_________
- 4y = 20 - x
Then divide both sides by - 4:
You will then get:
y =
From this equation we will only need the slope!
m || =
(This slope is for parallel)
but if you want perpendicular to the slope, then we need the negative reciprocal!
Negative reciprocal is a flipped version of the value that is negative, for example:
2 =
Because = 2
Now we will find the perpendicular slope which is:
m ⊥ = - 4
Now substitute this slope into slope intercept form:
y = mx + b
(-3) = -4(4) + b
(Take away parentheses)
-3 = -16 + b
(Move - 3 to the other side, by making it positive, but what you do to one side, you do to the other)
= -13 + 6
(Move - 13 to the other side, by make - 13 into +13)
+13 = +13
________
13 = b
(This is you b, also known as you intercept)
Your answer is:
y = -4x + 13