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Pachacha [2.7K]
3 years ago
10

How do you find interval of increase or decrease??

Mathematics
1 answer:
Virty [35]3 years ago
5 0
Using interval notation, it is described as increasing on the interval (1,3). Decreasing: A function is decreasing, if as x increases (reading from left to right), y decreases. In plain English, as you look at the graph, from left to right, the graph goes down-hill. The graph has a negative slope.
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Drag the point A to the location indicated in each scenario to complete each statement.
Art [367]

The graph from which the position of the point <em>A</em> can determined following

the multiplication with a scalar is attached.

Responses:

  • If <em>A</em> is in quadrant I and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant III</u>
  • If A is in quadrant II and is multiplied by a positive scalar, <em>c</em>, then c·A is in <u>quadrant II</u>
  • If <em>A</em> is in quadrant II and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant IV</u>
  • If <em>A</em> is in quadrant III and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant I</u>

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, <em>c</em>, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

  • c·A = c·a + c·b·i is in the <u>quadrant III</u> (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar <em>c</em>, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

  • c·A = -c·a + c·b·i is in <u>quadrant II</u>

Multiplying <em>A</em> by negative scalar if <em>A</em> is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant IV</u>

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying <em>A</em> with a negative scalar <em>c</em> gives;

c·A = c·a + c·b·i

c·a is positive

c·b  is positive

Therefore;

  • c·A = c·a + c·b·i is in<u> quadrant I</u>

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

4 0
3 years ago
Please help! I need this paper done before my class tomorrow! Thank you!
BabaBlast [244]

Answer:

x=7 and m<LMN = 120

Step-by-step explanation:

if MO bisects LMN then 13x - 31 must be equal to x + 53

13x - x = 53 + 31

12x = 84

x = 7

and

13x - 31 + x + 53 = m<LMN

14x + 22 = m<LMN

since x is 7

14×7 + 22 = 120

3 0
3 years ago
Read 2 more answers
The point slope form of a line with a slope of 2 through (1, 4) is y – 4 = 2(x – 1).
ella [17]

Answer:

TRUE

Step-by-step explanation:

y-4 = 2(x-1)

here, 4 is representing the y value and 1 is representing the x value.

And the slope is 2.

8 0
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Convert 28 cubic inches into cubic centimeters.
loris [4]

Answer:

458.838

Step-by-step explanation:

28 x 16.387 = <u>458.838</u>

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2 years ago
Find the product.<br> 2.05x0.47 =
pshichka [43]

Answer:

0.9625

Step-by-step explanation:

6 0
3 years ago
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