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DanielleElmas [232]
3 years ago
15

I NEED HELP help me get the answer

Mathematics
1 answer:
larisa86 [58]3 years ago
6 0

a. P(odd sum)

OK, each is drawing from a pile of 2 even cards and one odd, so have a 2/3 chance of picking even and a 1/3 chance of picking odd.

1/3 × 1/3 = 1/9 probability of odd+odd = even

1/3 × 2/3 = 2/9 prob of odd + even = odd

2/3 × 1/3 = 2/9 prob of even + odd = odd

2/3 × 2/3 = 4/9 prob of even+even = even

Total odd: 2/9+2/9 = 4/9

Answer: a) 4/9

b. P(sum < 11)

Let's just work out all the possibilities and count.

1st 2nd sum

4  4  8

4 5  9

4 6 10

5 4 9

5 5 10

5 6 11

6 4 10

6 5 11

6 6 12

I count 6 of 9 are less than 11, so P=6/9 or

Answer: b)  2/3

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\angle EFG\ \text{is supplementary to}\ \angle DBC\ \text{and}\\\\\angle ABC\ \text{is supplementary to}\ \angle DBC\ \text{therefore}\ m\angle EFG=m\angle ABC

18x+28+7x+27=180\\\\25x+55=180\ \ \ |-55\\\\25x=125\ \ \ \ |:25\\\\x=5\\\\m\angle EFG=(18x+28)^o=(18\cdot5+28)^o=118^o


\text{Answer: A)}\ 118^o

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