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Goshia [24]
3 years ago
10

True or false? if two triangles are congruent, then they can be moved so that they line up perfectly

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
5 0
<span>Yes they both will overlap each other perfectly meaning they will line up perfectly </span>
butalik [34]3 years ago
5 0

Answer:

true


Step-by-step explanation:


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The Bower family and the Jones family went to a restaurant and ordered food.
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Step-by-step explanation:

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It would be great if you could help me solve the circled question. It's regarding logarithms.
VARVARA [1.3K]

Answer:

x=1/8

Step-by-step explanation:

  1. 2²x-7×2x+6=0,4x-7×2x+6=0,4x×2x=0+7-6,8x=1,8x/8=1/8,8 will cancel 8 and x will stand alone so x=1/8
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3 years ago
A cube is shown.<br><br> What is the surface area of the cube?
valkas [14]

1350 cm^2.  First, we must find the area of one side.  The formula for the area of a square is S^2 or S*S, so plugging in the value of the side we get 15*15=225.  So each side of the cube is 225 cm^2, so since there are 6 sides, we just multiply by 6 (225*6=1350).

4 0
3 years ago
Read 2 more answers
Tom is going to USA on holiday. he changes £500 to U.S dollar. the exchange rate is £1=$1. 51. how much dollar will he get​
dangina [55]

500 x 1.51

=$755

∴ He will get $755.

7 0
3 years ago
What is the average rate of change of f(x) = (x + 3)2 − 2
Tema [17]

Answer:

When we have a function f(x), the average rate of change in the interval (a, b) is:

r = \frac{f(b) - f(a)}{b - a}

In this case, we have the function:

f(x) = (x + 3)^2 - 2

(but we do not have the interval, and I couldn't find the complete question online)

So if for example, we have the interval (2, 4)

The average rate of change will be:

r = \frac{(4 + 3)^2 - 2 - (2 + 3)^2 + 2}{4 - 2}  = \frac{24}{2} = 12

If instead, we want the rate of change in a differential dx around the value x, we need to differentiate the function (this is way more complex, so I will define some rules first).

Such that the rate of change, in this case, will be:

f'(x) = df/dx

For a function like:

g(x) = x^n + c

g'(x) = n*x^(n - 1)

And for:

h(x) = k( g(x))

h'(x) = k'(g(x))*g'(x)

So here we can write our function as:

f(x) = k(g(x)) = (x + 3)^2 - 2

where:

g(x) = x + 3

k(x) = x^2 - 2

Then:

f'(x) = 2*(x + 3)*1 = 2*x + 6

That is the rate of change as a function of x (but is not an "average" rate of change)

8 0
3 years ago
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