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Marina86 [1]
4 years ago
14

Help me answer these questions

Chemistry
1 answer:
9966 [12]4 years ago
8 0

Answer:

<h3><em>We're sorry, we don't understand. Please type in your question and we'll respond as soon as we can.</em></h3>

Explanation:

Hope that helped........ :)

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How many moles are in 68 grams of Mg(OH)
klemol [59]

Answer:

1.16 mol

Explanation:

Given data:

Mass in gram Mg(OH)₂ = 68 g

Number of moles of Mg(OH)₂ = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of Mg(OH)₂ = 58.32 g/mol

By putting values,

Number of moles = 68 g/ 58.32 g/mol

Number of moles = 1.16 mol

4 0
3 years ago
The density of solid Ag is 10.5 g/cm3. How many atoms are present per cubic centimeter of Ag?
Sveta_85 [38]

Answer:

Unit cells which are present per cubic centimeter of Ag = =1.45\times 10^{22}\ unit\ cells /cm^3

Volume = 68.9\times 10^{-24}\ cm^3

Edge length = 4.1\times 10^{-8}\ cm

Explanation:

(a)

Given that:-

The density of the solid Ag = 10.5 g/cm³

Molar mass of silver = 107.8682 g/mol

So, Moles present per cm³ of Ag = \frac{10.5\ g/cm^3}{107.8682\ g/mol}=0.0973 mol/cm³

Also, 1 mole = 6.023\times 10^{23} atoms.

So,

Atoms present per cm³ of Ag = 0.0973\ mol/cm^3\times 6.023\times 10^{23}\ atoms/mol=5.8\times 10^{22}\ atoms/cm^3

Thus, answer = 5.8\times 10^{22}\ atoms/cm^3

In FCC, the number of atoms  in the unit cell = 4 unit cells

So,

Unit cells which are present per cubic centimeter of Ag = \frac{5.8\times 10^{22}\ atoms/cm^3}{4}=1.45\times 10^{22}\ unit\ cells /cm^3

<u>Unit cells which are present per cubic centimeter of Ag = =1.45\times 10^{22}\ unit\ cells /cm^3</u>

(b)

The reciprocal of the unit cell/cm³ is the volume of the unit cell.

So, Volume=\frac{1}{1.45\times 10^{22}\ unit\ cells /cm^3}=68.9\times 10^{-24}\ cm^3

<u>Volume = 68.9\times 10^{-24}\ cm^3</u>

(c)

Also, Volume = {(Edge\ length)}^3

Thus, edge length = {Volume}^{\frac{1}{3}} = \left(68.9\times \:\:10^{-24}\right)^{\frac{1}{3}}\ cm=4.1\times 10^{-8}\ cm

<u>Edge length = 4.1\times 10^{-8}\ cm</u>

5 0
4 years ago
Can someone SCIENTIFICALLY explain to me the formation of all types of Acid Rain?<br> Plz
faust18 [17]

so basically

some fuels have an impurity in them which is sulfur.

When the fuel undergoes combustion, the sulfur reacts with oxygen in the air to form sulfur dioxide.

the sulfur dioxide reacts with water vapour in the air to form sulfurous acid, which is a type of acid rain.

Also

the high pressures inside a car engine may cause nitrogen and oxygen in the air to react and form oxides of nitrogen. the most common compounds formed inside car engines are NO (nitrogen oxide) and NO2 (nitrogen dioxide)

8 0
3 years ago
Sally has touched a hot pan on the stove and burnt her hand. This example shows what type of heat transfer?
Minchanka [31]

Answer:

Transfer of Heat

You might have observed that a frying pan becomes hot when kept on a flame. It is because the heat passes from the flame to the utensil. When the pan is removed from the fire, it slowly cools down. Why does it cool down? The heat is transferred from the pan to the surroundings. So you can understand that in both cases, the heat flows from a hotter object to a colder object. In fact, in all cases heat flows from a hotter object to a colder object.

Explanation:

please make me as brainleist

6 0
3 years ago
The table shows the chemical formulas for four substances. Which substance have the same numbers of carbo atoms?
mr_godi [17]

Answer:

Explanation:

you are beautiful

6 0
3 years ago
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