Answer:
option A
Explanation:
given,
Length of boat = 4 m
width of boat = 2 m
height up to which water is displaced = 1 m
Volume of water displaced by the boat
V = L x B x H
V = 4 x 2 x 1
V = 8 m³
buoyant force acting on the boat
F_b = ρ g V
m g = ρ g V
m = ρ V
ρ is the density of water which is equal to 1000 Kg/m³
m = ρ V
m =1000 x 8
m = 8000 Kg
hence, mass of the boat is equal to 8000 Kg
so, the correct answer is option A
In a Class One Lever, the Fulcrum is located between the Load and the Force.
By testing it out. Try it.
The planets all formed from this spinning disk-shaped cloud, and continued this rotating course around the Sun after they were formed. The gravity of the Sun keeps the planets in their orbits. They stay in their orbits because there is no other force in the Solar System which can stop them.
Answer:
If the track is horizontal and the string is pulled horizontally, the friction on the cart would be 
.
Explanation:
Let 
denote the mass of this cart, and let 
denote the acceleration of this cart.
.
.
Apply Newton's Second Law to find the net force on this cart.
.
The following forces act upon this cart:
- (downward) gravitational attraction from the earth,
- (upward) normal force from the track,
- (forward) tension from the string, and
- (backward) friction from the track.
Assume that the track is horizontal, and that the string was pulled horizontally. The normal force from the track would exactly balance the downward gravitational attraction from the earth. Hence, the 
net force on this cart would be equal (in size) to the size of the tension from the string (
) minus the size of the friction from the track.
In other words:
.
.
.
