How do we know that water dissolves glue?

kumpel [21]

I think it’s ( Only the arm length should be changed. The mass should remain the same )

8 0

4 years ago

A wire carrying a current of 2.85 A has a straight segment of 2.35 m. Determine the magnitude of the magnetic field due to this

mihalych1998 [28]

Answer:

$2.02\times 10^{-6} T$

Explanation:

We are given that

Current,I=2.85 A

Length of segment=l=2.35 m

d=0.275 m

We have to find the magnitude of magnetic field due to this segment of wire at a point P which is at midpoint of the straight wire.

$r=\frac{l}{2}=\frac{2.35}{2}=1.175 m$

$\theta=tan^{-1}(\frac{r}{d})=tan^{-1}(\frac{1.175}{0.275})=76.82^{\circ}$

$\theta=\theta_1=\theta_2$

Magnetic field,B= $\frac{\mu_0I}{4\pi d}(sin\theta_1+sin\theta_2)=\frac{\mu_0I}{4\pi d}(2sin\theta)$

Where $\frac{\mu_0}{4\pi}=10^{-7}$

Using the formula

$B=\frac{10^{-7}\times 2.85}{0.275}(2sin(76.82))=2.02\times 10^{-6} T$

5 0

4 years ago

3 ways how natural disasters impact environment.

Trava [24]

1. When sewage treatment plants flood or debris reaches reservoirs and streams, the quality of the water is affected.

2. Storm surges cause beaches to shift and alter shape.

3. During flash floods, riverbanks erode.

5 0

3 years ago

A rectangular loop of area A is placed in a region where the magnetic field is perpendicular to the plane of the loop. The magni

mina [271]

Answer:

Induced emf, $\epsilon=-A\dfrac{B_{max}e^{-t/\tau}}{\tau}$

Explanation:

The varying magnetic field with time t is given by according to equation as :

$B=B_{max}e^{-t/\tau}$

Where

$B_{max}\ and\ t$ are constant

Let $\epsilon$ is the emf induced in the loop as a function of time. We know that the rate of change of magnetic flux is equal to the induced emf as:

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{d(BA)}{dt}$

$\epsilon=-A\dfrac{d(B)}{dt}$

$\epsilon=-A\dfrac{d(B_{max}e^{-t/\tau})}{dt}$

$\epsilon=A\dfrac{B_{max}e^{-t/\tau}}{\tau}$

So, the induced emf in the loop as a function of time is $A\dfrac{B_{max}e^{-t/\tau}}{\tau}$ . Hence, this is the required solution.

7 0

3 years ago

Two gravitational forces act on a particle, in perpendicular directions. to find the net force, can we add the magnitudes of tho

Anna71 [15]

No, we can not add the magnitudes of those two forces.

<h3>What is Gravitational Force?</h3>

An attractive force between masses is a gravitational force. According to Isaac Newton's second law, F = ma, a gravitational force generates an acceleration just like all other forces do. Remember that according to Newton's second law, a body will accelerate if there is a net force acting on it in an inertial frame of reference (a coordinate system travelling at a constant speed). According to Newton's Universal Law of Gravitation, when two bodies, such as the Earth and the Sun, are in close proximity to one another, an attractive force naturally attracts them. This attraction results in an acceleration of the two objects.

To learn more about Gravitational Force, visit:

brainly.com/question/12528243

#SPJ4

6 0

2 years ago