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inysia [295]
3 years ago
8

A boat is 4.0meters long and 2.0meters wide. Its water line is 1.0meter from the bottom of the boat; it is submerged to this wat

er line. What is the mass of the boat? A. 8000kgB. 600kgC. 130kgD. 800kgE. 200kg
Physics
1 answer:
Mademuasel [1]3 years ago
3 0

Answer:

option A

Explanation:

given,

Length of boat = 4 m

width of boat = 2 m

height up to which water is displaced = 1 m

Volume of water displaced by the boat

 V =  L x B x H

 V = 4 x 2 x 1

 V = 8 m³

buoyant force acting on the boat

F_b = ρ g V

m g = ρ g V

 m = ρ V

ρ is the density of water which is equal to 1000 Kg/m³

 m = ρ V

 m =1000 x 8

 m = 8000 Kg

hence, mass of the boat is equal to 8000 Kg

so, the correct answer is option A

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An object is moving with a constant velocity of 278 m/s. How long will it take it to travel 7500 m, using the formula Delta X=Vt
rusak2 [61]
If the velocity is constant then the acceleration of the object is zero.
a=0 (m/s^2)
Thus when we apply the equation
\Delta X=vt+(at^2/2)
It remains
\Delta X =vt
or equivalent
t=(\Delta X/v) =7500/278 =26.98 (seconds)

7 0
3 years ago
Sam is pulling a box up to the second story of his apartment via a string. The box weighs 53.3 kg and starts from rest on the gr
castortr0y [4]

Answer:

W = 1222.4 J = 1.22 KJ

Explanation:

The work done on an object is the product of the force applied on it and the displacement it covers as a result of this force. It must be noted that the component of displacement in the direction of force should only be used. Hence, the work can be calculated as:

W = F d Cosθ

where,

W = Work Done = ?

F = Force Applied = 64 N

d = Distance Covered by Box = 19.1 m

θ = Angle between force and displacement = 0°

Therefore,

W = (64 N)(19.1 m)Cos 0°

<u>W = 1222.4 J = 1.22 KJ</u>

7 0
2 years ago
a ultrasonic wave at 8x10^4 Hz is emitted into a vien where the speed of sound in blood is 1570 m/s. the wave reflects off the r
Aneli [31]

Answer: 0.392 m/s

Explanation:

The Doppler shift equation is:

f'=\frac{V+V_{o}}{V-V_{s}} f

Where:

f=8(10)^{4} Hz is the actual frequency of the sound wave

f'=8.002(10)^{4} Hz is the "observed" frequency

V=1570 m/s is the speed of sound

V_{o}=0 m/s is the velocity of the observer, which is stationary

V_{s} is the velocity of the source, which are the red blood cells

Isolating V_{s}:

V_{s}=\frac{V(f'-f)}{f'}

V_{s}=\frac{1570 m/s(8.002(10)^{4} Hz-8(10)^{4} Hz)}{8.002(10)^{4} Hz}

Finally:

V_{s}=0.392 m/s

3 0
3 years ago
A car traveling with constant speed travels 150 km in 7200s. What is the speed of the car?
LiRa [457]
Speed= distance/time
Speed= 150000m/7200s=20.83m/s(cor.to.2d.p.)
7 0
3 years ago
According to Kepler's Second Law the radius vector drawn from the Sun to a planet Multiple Choice is the same for all planets. s
Mademuasel [1]

Answer:

sweeps out equal areas in equal times.

Explanation:

As we know that there is no torque due to Sun on the planets revolving about the sun

so we will have

\tau_{net} = 0

now we have

\frac{dL}{dt}= 0

now we also know that

Area = \frac{1}{2}r^2d\theta

so rate of change in area is given as

\frac{dA}{dt} = \frac{1}{2}r^2\frac{d\theta}{dt}

so we will have

\frac{dA}{dt} = \frac{1}{2}r^2\omega

\frac{dA}{dt} = \frac{L}{2m}

since angular momentum and mass is constant here so

all planets sweeps out equal areas in equal times.

4 0
3 years ago
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