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butalik [34]
3 years ago
5

Which class of lever do spoon and scissors belong to?​

Physics
2 answers:
balandron [24]3 years ago
8 0
In a Class One Lever, the Fulcrum is located between the Load and the Force.
Goshia [24]3 years ago
7 0

Answer:

spoon and scissors belong to first class lever.

hope it is helpful to you

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If railroad tracks were built over the boundary of two plates what would happen to the railroad tracks as the plates moved
Oliga [24]
The railroad tracks will move with the plate boundaries
6 0
3 years ago
What forces control the strength of the tides
Colt1911 [192]

Answer:

Gravity is one major force that creates tides. In 1687, Sir Isaac Newton explained that ocean tides result from the gravitational attraction of the sun and moon on the oceans of the earth (Sumich, J.L., 1996).

Explanation:

I hope this helps.

7 0
2 years ago
Read 2 more answers
Chapter 14, Problem 042 A flotation device is in the shape of a right cylinder, with a height of 0.588 m and a face area of 4.19
Alisiya [41]

Answer:

The workdone is  W = 9.28 * 10^{3} J

Explanation:

From the question we are told that

   The height of the cylinder is  h = 0.588\ m

   The face Area is  A = 4.19 \ m^2

    The density of the cylinder is \rho  =  0.346 * \rho_w

     Where \rho_w is the density of freshwater which has a constant value

              \rho_w = 1000 kg/m^3

     

Now  

     Let the final height of the device under the water be  =  h_f

      Let  the initial volume underwater be = V_n

     Let the initial height under water be  = h_i

      Let the final volume under water be  = V_f

According to the rule of floatation

        The weight of the cylinder =  Upward thrust

This is mathematically represented as

          \rho_c g V_n = \rho_w gV_f

         \rho_c A h = \rho A h_f

So      \frac{0.346 \rho_w}{\rho_w} = \frac{h_f}{h}

   =>     \frac{h_f}{h_c}  = 0.346

Now the work done is mathematically represented as  

          W = \int\limits^{h_f}_{h} {\rho_w g A (-h)} \, dh

               =   \rho_w g A [\frac{h^2}{2} ] \left | h_f} \atop {h}} \right.

              = \frac{g A \rho}{2}  [h^2 - h_f^2]

              = \frac{g A \rho}{2} (h^2)  [1  - \frac{h_f^2}{h^2} ]

Substituting values

        W = \frac{(9.8 ) (4.19) (10^3)}{2} (0.588)^2 (1 - 0.346)

        W = 9.28 * 10^{3} J

4 0
2 years ago
In moving out of a dormitory at the end of the semester, a student does 1.82 x 104 J of work. In the process, his internal energ
emmainna [20.7K]

Answer:

Explanation:

(a) Work done, W = 1.82 x 10^4 J

(b) internal energy, U = - 4.07 x 10^4 J ( as it decreases)

(c) According to the first law of thermodynamics  

Q = W + U

Q = 1.82 x 10^4 - 4.07 x 10^4

Q = - 2.25 x 10^4 J

4 0
3 years ago
What gives the gem amethyst it's purplish color?
-Dominant- [34]
  i think its iron... 
<span>Presence of trace elements, irradiation and iron impurities give the gem its purplish color . 
:))
merry christmas</span>
3 0
2 years ago
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