Answer:
7.5
Step-by-step explanation:
The relation between time, speed, and distance is ...
time = distance/speed
If distance is "1 round trip", then the time going is ...
going = 0.5/(10 mi/h) . . . . for 1/2 round trip
and the time coming is ...
coming = 0.5/(6 mi/h)
Then the average speed for the full round trip is ...
speed = distance/time
average speed = 1/(going + coming) = 1/(0.5/10 +0.5/6) mi/h
= 1/((3+5)/60) mi/h
= 60/8 mi/h = 7.5 mi/h
Jack's average speed for the round trip was 7.5 mph.
Answer: I'm guessing it would be a parabola, with the line going through -6 on the y-axis and passing through 2 and 6 on the x-axis, but we cannot see any answers, so therefore we can't answer it accurately.
Step-by-step explanation:
Answer:
the width=15; the length=20
Step-by-step explanation:
1. to solve the given equation: x²+5x-300=0;
x₁= -20; x₂=15, where 'x' can be only positive value. It means x=15;
2. according to the condtition the length is more, it means 15+5=20.
3. the width is x=15; the length is 20.
Answer:
The answer should be 120.
Step-by-step explanation:
30% of 400 = 120 cats
When finding the percent difference between two numbers, there are two ways you can do this.
1. The first way is how to calculate the percentage INCREASE of two numbers:
-The formula is Increase / Original Number × 100 = % increase
Step 1: Find out the difference between the two numbers you're comparing. New number - Original number = Increase.
Step 2: Divide the increase by the original number and then multiply your answer by 100. (If your answer is a negative number, then it is a percent decrease, not a percent increase.)
2. The second way is how to calculate the percentage DECREASE of two numbers:
Step 1: Find out the difference between the two numbers you're comparing. Original number - New number = Decrease.
Step 2: Divide the decrease by the original number and then multiply your answer by 100. Decrease ÷ Original Number × 100
= % Decrease. (If your answer is a negative number, then is is a percent increase, not a percent decrease.)
