All categories

3 years ago

Will you play surviv.io with me and join my team right now please because I need some friends

Computers and Technology

2 answers:

igomit [66]3 years ago

6 0

Answer:

lets play dude!!

Explanation:

Sergeu [11.5K]3 years ago

5 0

Answer:

i play

Explanation:

when will we play

You might be interested in

The _________ in an internet are responsible for receiving and forwarding packets through the interconnected set of networks and

raketka [301]

Answer:

routers

Explanation:

<h2><em><u>Fill in the blanks</u></em></h2>

The<u> routers </u> in an internet are responsible for receiving and forwarding packets through the interconnected set of networks and making routing decisions based on knowledge of the topology and traffic/delay conditions of the internet.

3 0

3 years ago

The Bradshaw family has $200,000 of total assets and $140,000 of liabilities. What is their net worth?

3241004551 [841]

Answer:

$340,000 is there net worth

Explanation:

$200,000+ $140,000 = $340,000

5 0

3 years ago

A testing lab wishes to test two experimental brans of outdoor pain long each wiil last befor fading . The testing lab makes six

Simora [160]

Answer:

The answer is " $\bold{Brand \ A \ (35, 350, 18.7) \ \ Brand \ B \ (35, 50, 7.07)}$ "

Explanation:

Calculating the mean for brand A:

$\to \bar{X_{A}}=\frac{10+60+50+30+40+20}{6} =\frac{210}{6}=35$

Calculating the Variance for brand A:

$\sigma_{A}^{2}=\frac{\left ( 10-35 \right )^{2}+\left ( 60-35 \right )^{2}+\left ( 50-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 20-35 \right )^{2}}{5} \\\\$

$=\frac{\left ( -25 \right )^{2}+\left ( 25 \right )^{2}+\left ( 15\right )^{2}+\left ( -5 \right )^{2}+\left ( 5 \right )^{2}+\left ( 15 \right )^{2}}{5} \\\\ =\frac{625+ 625+225+25+25+225}{5} \\\\ =\frac{1750}{50}\\\\=350$

Calculating the Standard deviation:

$\sigma _{A}=\sqrt{\sigma _{A}^{2}}=18.7$

Calculating the Mean for brand B:

$\bar{X_{B}}=\frac{35+45+30+35+40+25}{6}=\frac{210}{6}=35$

Calculating the Variance for brand B:

$\sigma_{B} ^{2}=\frac{\left ( 35-35 \right )^{2}+\left ( 45-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 35-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 25-35 \right )^{2}}{5}$

$=\frac{\left ( 0 \right )^{2}+\left ( 10 \right )^{2}+\left ( -5 \right )^{2}+\left (0 \right )^{2}+\left ( 5 \right )^{2}+\left ( -10 \right )^{2}}{5}\\\\=\frac{0+100+25+0+25+100}{5}\\\\=\frac{100+25+25+100}{5}\\\\=\frac{250}{5}\\\\=50$

Calculating the Standard deviation:

$\sigma _{B}=\sqrt{\sigma _{B}^{2}}=7.07$

4 0

3 years ago

What is the quick key to highlighting a column?

BaLLatris [955]

Answer:

B is the answer.. pls mark me as brainliest

ctrl+shift+down arrow

Explanation:

7 0

3 years ago

Regular languages are closed under complement. True False

aivan3 [116]

Answer: True

Explanation:

A language is said to be closed under a operation here the complement is the operation then if upon application of that operation to any members of that language always yields a member of that language.

regular languages are closed under complement. A proof of the statement is

If a regular language 'L' is regular then there is a DFA X recognizing that regular language 'L'. to show that L' (compliment) is regular we need to have another DFA X' recognizing L'.

The initial state and transition function of both the DFAs are same except their accepting state. Then we can say that X' accepts L'.

So, we can say that regular languages are closed under complement.

4 0

3 years ago