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EleoNora [17]
2 years ago
12

Alice had $4.80 left after spending 40 percent of her money on lunch, 20 percent of what was left after lunch on parking, and 50

percent of what was left at a café. How much money did Alice have before lunch?
Mathematics
1 answer:
Vitek1552 [10]2 years ago
8 0

Answer:

$20

Step-by-step explanation:

We are given the percentages of how much she spent on each purchase but we need the percentage of what is left after each purchase. We calculate this by subtracting each percentage from 100% like so.

100% - 40% = 60%

100% - 20% = 80%

100% - 50% = 50%

Next we need to do is change the percentages into decimal format. We do this by moving the decimal 2 digits to the left. Therefore the percentages wasted are the following

60.0%   ⇔   0.60

80.0%   ⇔   0.80

50.0%   ⇔   0.50

Now that we have the percentages in decimal format we can calculate the total price (t) by retracing the spending process. The spending process was following.

t_{2} = 0.60t

t_{3} = 0.80t_{2}

4.80 = 0.50t_{3}

So we have to retrace by solving for t_{3}, then t_{2}, and finally (t)

4.80 = 0.50t_{3} ... divide both sides by 0.50

9.60 = t_{3}

9.60 = 0.80t_{2} .... divide both sides by 0.20

12 = t_{2}

12 = 0.60t  .... divide both sides by 0.60

20 = t

Finally we can see that the Total amount of money that Alice had before lunch was $20

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Answer:

\huge\boxed{y=-\frac{1}{7}x+ 10}

Step-by-step explanation:

In order to find the equation of this line, we need to note two things.

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So first, let's find the opposite reciprocal of 7 which will be the slope to this equation.

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So the slope of this line will be -\frac{1}{7}. The y-intercept will change, and we can substitute what we know into the equation y=mx+b.

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Now that we know the y-intercept, we can finish off our equation by plugging that in.

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