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3 years ago

418.6 divided by 80.5

Mathematics

2 answers:

MArishka [77]3 years ago

6 0

5.2 is the answer to your problem

Natali5045456 [20]3 years ago

6 0

And the answerrrrrr issssss 5.2! :)

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What is the difference to the nearest hundredth of a unit between the two zeros

Luda [366]

Answer:

0.1

Step-by-step explanation:

hwhhehhejejeejjrjr

3 0

3 years ago

there are 104 red candies in a candy machine. this represents 26% of the candy in the machine. how many total are in the candy m

Alborosie

There are 400 candies in the machine.

Step-by-step explanation:

Given,

Number of red candies in machine = 104

This represents 26% of the total candies.

Let,

x be the total candies in the machine.

According to statement;

26% of x = 104

$\frac{26}{100}*x=104\\0.26x=104$

Dividing both sides by 0.26

$\frac{0.26x}{0.26}=\frac{104}{0.26}\\x=400$

There are 400 candies in the machine.

Keywords: percentage, division

Learn more about percentages at:

#LearnwithBrainly

6 0

3 years ago

Suppose that a fast food restaurant decides to survey its customers to gauge interest in a breakfast menu. After surveying multi

Harlamova29_29 [7]

Answer:

$ME= \frac{Width}{2}=\frac{0.078}{2}=0.039$

$\hat p =0.688+0.039=0.727$

$\hat p =0.766-0.039=0.727$

Step-by-step explanation:

Assuming that the confidence interval is (0.688; 0.766)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

Use the confidence interval to find the point estimate and margin of error for the proportion

The margin of error is given by :

$Me=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And for our case we can find the width of the confidence interval like this:

Width =0.766-0.688=0.078

And the estimation for the margin of error would be given by:

$ME= \frac{Width}{2}=\frac{0.078}{2}=0.039$

Now we can find th point of estimate adding the margin of error to the lower limit of the interval or subtracting the margin of error to the upper limit, like this:

$\hat p =0.688+0.039=0.727$

$\hat p =0.766-0.039=0.727$

4 0

3 years ago

Graph the line y=kx+1 if it is known that the point M belongs to it: m(1,3)

Novosadov [1.4K]

Answer:

y = 2x +1

Step-by-step explanation:

y=kx+1

Substitute the point into the equation

3 = k(1) + 1

3 = k+1

Subtract 1 from each side

3-1 = k

2 = k

y = 2x +1

The slope is 2 and the y intercept is 1

3 0

3 years ago

Read 2 more answers

He statement below describes a situation in which opposite quantities combine to make zero:

kozerog [31]

False I’m pretty sure

3 0

2 years ago